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3 years ago

A Tessellation has no________. A) gaps or overlaps B) translations C) repeated figures

1 answer:

ozzi3 years ago

8 0

A tessellation has no A) gaps or overlaps, as a tessellation is all about repeated figures, which can be translated onto other figures, this produces a pattern.

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Can an octagon have interior angles that measure 100 degrees, 156 degrees, 125 degrees, 90 degrees, 175 degrees, 160 degrees, an

worty [1.4K]

9514 1404 393

Answer:

yes

Step-by-step explanation:

The 7 angles listed have a total of 946 degrees. The total interior angle measure in an octagon is 1080 degrees. So, the remaining angle must have a measure of 134°. The figure is entirely feasible.

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2 years ago

To solve the equation, Antwan uses the distributive property, combines like terms, then uses the addition and subtraction proper

Lady_Fox [76]

The answer is c-20 or 5

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3 years ago

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Thompson and Thompson is a steel bolts manufacturing company. Their current steel bolts have a mean diameter of 141 millimeters,

tiny-mole [99]

Answer:

Probability that the sample mean would be greater than 141.4 millimetres is 0.3594.

Step-by-step explanation:

We are given that Thompson and Thompson is a steel bolts manufacturing company. Their current steel bolts have a mean diameter of 141 millimetres, and a standard deviation of 7.

A random sample of 39 steel bolts is selected.

Let $\bar X$ = sample mean diameter

The z score probability distribution for sample mean is given by;

Z = $\frac{ \bar X-\mu}{\frac{\sigma}{\sqrt{n} } } }$ ~ N(0,1)

where, $\mu$ = population mean diameter = 141 millimetres

$\sigma$ = standard deviation = 7 millimetres

n = sample of steel bolts = 39

Now, Percentage the sample mean would be greater than 141.4 millimetres is given by = P( $\bar X$ > 141.4 millimetres)

P( $\bar X$ > 141.4) = P( $\frac{ \bar X-\mu}{\frac{\sigma}{\sqrt{n} } } }$ > $\frac{141.4-141}{\frac{7}{\sqrt{39} } } }$ ) = P(Z > 0.36) = 1 - P(Z $\leq$ 0.36)

= 1 - 0.6406 = 0.3594

The above probability is calculated by looking at the value of x = 0.36 in the z table which has an area of 0.6406.

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3 years ago

A manufacturer produces a commodity where the length of the commodity has approximately normal distribution with a mean of 6.5 i

zavuch27 [327]

The probablity that the sample's mean length is greate than 6.3 inches is0.8446.

Given mean of 6.5 inches,standard deviation of 0.5 inches and sample size of 46.

We have to calculate the probability that the sample's mean length is greater than 6.3 inches is 0.8446.

Probability is the likeliness of happening an event. It lies between 0 and 1.

Probability is the number of items divided by the total number of items.

We have to use z statistic in this question because the sample size is greater than 30.

μ=6.5

σ=0.5

n=46

z=X-μ/σ

where μ is mean and

σ is standard deviation.

First we have to find the p value from 6.3 to 6.5 and then we have to add 0.5 to it to find the required probability.

z=6.3-6.5/0.5

=-0.2/0.5

=-0.4

p value from z table is 0.3446

Probability that the mean length is greater than 6.3inches is 0.3446+0.5=0.8446.

Hence the probability that the mean length is greater than 6.3 inches is 0.8446.

Learn more about probability at brainly.com/question/24756209

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2 years ago

Melanie is very concerned with avoiding late fees. The table shows her choices for paying her bills. Method Bill Payment Methods

pshichka [43]

Answer:

Step-by-step explanation:

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3 years ago

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