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Black_prince [1.1K]
4 years ago
14

A Tessellation has no________. A) gaps or overlaps B) translations C) repeated figures

Mathematics
1 answer:
ozzi4 years ago
8 0
A tessellation has no A) gaps or overlaps, as a tessellation is all about repeated figures, which can be translated onto other figures, this produces a pattern.<span />
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In the figure at the right DC = 20 cm and AB =36 cm . what is FE? a.16cm b.56cm c.28cm d.46cm​
puteri [66]

Answer:

however dc =20 cm is

Step-by-step explanation:

so this isnt contrary to 50

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31/9 as a mix number
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3 and 4/9 would be the answer to this.
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Write a step by step procedure for determining the area of the figure below.
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3 years ago
Let V be the volume of the solid obtained by rotating about the y-axis the region bounded y = 25x and y = x2 25 . Find V by slic
vesna_86 [32]

Answer:

volume\ = \pi \frac{625^2}{6}

Step-by-step explanation:

See the attached figure.

y₁ = 25x  and  y₂ =x²

The intersection between y₁ and y₂

25x = x²

x² - 25x = 0

x(x-25) = 0

x = 0 or x =25

y = 0 or y =25² = 625

The points of intersection (0,0) and (25,625)

To find the volume of the solid obtained by rotating about the y-axis the region bounded by y₁ and y₂

y₁ = 25x ⇒ x₁ = y/25 ⇒ x₁² = y²/625

y₂ =x² ⇒ x₂ = √y ⇒ x₂² = y

v = ∫A(y) dy = π ∫ (x₂² - x₁²) dy

∴ V =

\pi \int\limits^{625}_0 {y-\frac{y^2}{625} } \, dy  =\pi( \frac{y^2}{2} -\frac{y^3}{3*625} ) =\pi (\frac{625^2}{2} -\frac{625^3}{3*625}) =\pi ( \frac{625^2}{2}-\frac{625^2}{3}) =\pi \frac{625^2}{6}

8 0
3 years ago
The sum of two numbers is 30 and their difference is 12, what are the two numbers
Tju [1.3M]

Step-by-step explanation:

Let the number is a <em>and</em><em> </em>b

The sum of two numbers =30

so,a+b=30 <em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>(</em><em>1</em><em>)</em>

The difference of two number =12

so,a-b=12<em> </em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>(</em><em>2</em><em>)</em>

If we add two equation (1) and (2)

we get,

a+b+a-b=30+12

2a=42

\tt{ a=\dfrac{42}{2}  }

\tt{  a=21 }

so,one number is a=21

if we put the value a in (2) equation

we get,

a-b=12

21-b=12

b=21-12

b=9

so,the another number is=b=9

\tt{ the~two~ number~ are~ 21 ~and~ 9  }

3 0
3 years ago
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