All categories

3 years ago

Help :) Answer this fast plss

Mathematics

1 answer:

irina1246 [14]3 years ago

8 0

Answer: I think 70 percent

Step-by-step explanation:

You might be interested in

What is 55005005050 x464537226228

alexira [117]

Answer:

2.5551872e+22

Step-by-step explanation:

7 0

3 years ago

Problem 8) In the diagram, RQ ⊥ PQ, m∠QPS = 32°, m∠RPS = 24°, and PQ = 14.Find RS to the nearest tenth of a unit. Image is provi

Sav [38]

Since S is a point on the segment QR, then:

$QS+SR=QR$

Use the diagram and trigonometric relationships to find the value of QS and QR. Then, use the above equation to solve for SR.

In the right triangle PQS, the side QS is opposite to the angle of 32º, and the side PQ is adjacent to the angle of 32º. Then, use the tangent trigonometric function to relate PQ to QS:

$\tan\left(32º\right)=\frac{QS}{PQ}$

Isolate QS and replace PQ=14:

$\begin{gathered} \Rightarrow QS=PQ\cdot\tan\mleft(32º\mright) \\ \operatorname{\Rightarrow}QS=14\tan\mleft(32º\mright) \end{gathered}$

On the other hand, notice that the side QR in the right triangle PQR is opposite to the angle QPR, which has a measure of 32º+24º=56º.

Then, by a similar reasoning, we can use again the tangent function to find QR:

$\begin{gathered} \tan\mleft(56º\mright)=\frac{QR}{PQ} \\ \Rightarrow QR=PQ\cdot\tan\mleft(56º\mright) \\ \Rightarrow QR=14\cdot\tan\mleft(56º\mright) \end{gathered}$

We have found expressions for QS and QR in terms of trigonometric relationships. Then, we can find an expression for SR:

$\begin{gathered} QS+SR=QR \\ \Rightarrow SR=QR-QS \end{gathered}$

Replace the expressions for QR and QS:

$SR=14\tan\mleft(56º\mright)-14\tan\mleft(32º\mright)$

Use a calculator to find decimal expressions for tan(56º) and tan(32º). Then, find SR:

$\begin{gathered} SR=14\times1.482560969...-14\times0.6248693519... \\ \Rightarrow SR=12.00768263... \end{gathered}$

Therefore, to the nearest tenth, the length of the side SR (or RS, which is the same) is 12.0.

3 0

1 year ago

What is the total amount, in cups, of four required for each cup of chocplate using this cake recipe?

Orlov [11]

6 7/8 -> 55/8 /5= 11/8*6= 66/8 /2 = 33/4

7 0

3 years ago

When the volume of a gas is

Fudgin [204]

Answer: The initial volume is 593.76mL

Step-by-step explanation:

As you do not say anithing about the pressure, i guess that the pressure remains constant.

If the gas is an ideal gas, we have:

P*V = n*R*T

where P is pressure, n is number of moles and R is a constant.

Now, initially we have:

P*Vi = n*R*315°C

finally we have:

P*825mL = n*R*452°C

Now we can take the quiotient of those two equations and get:

(P*Vi)/(P*852mL) = (n*R*315°C)/( n*R*452°C)

Now we have:

Vi/852mL = 315/452

Vi = (315/452)*852mL = 593.76mL

So when we expand the gas at constant pressure, we increase the temperature.

3 0

3 years ago

Noaya read a book cover to cover in a single session, at a rate of 55 pages per hour. After 4 hours, he had 350 pages left to re

natali 33 [55]

Answer:

55 pages/hour

350 - 55x = y

6 0

3 years ago