What is the value of a and b if a times b =88 and a and b differ by32
1 answer:
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Following are the general entry to the given question:
For Question 1:
Date Account Titles and Explanation Dr Cr
31-Jan-2024 Revenue Service $17,500
Summary of Income $17,500
(Finishing the revenue account)
31-Jan-2024 Summary of Income $7,100
Expense of Salary $3,600
Expense on rent $1,800
Expense of Depreciation - equipment $300
Expense on Supplies $400
Expense on Utilities $1,000
(To close the expenditure account)
31-Jan-2024 Summary of Income $10,400
Retained Earnings $10,400
(To bring net income into line with retained profits)
31-Jan-2024 Retained Earnings $1,000
Dividend $1,000
(To close net dividend to retained earnings)
For Question 2:
A net income of $10,400 is generated. They may compute it by subtracting total expenses from the entire revenue.
Total Revenue= $17,500
Total Expenses=$7,100
- Please find the complete question in the attachment file.
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9514 1404 393
Answer:
- positive
- negative
Step-by-step explanation:
The thrust of the question is to make sure you understand that increasing the y-coordinate of a point will move the point upward, and decreasing it will move the point downward.
That is adding a positive value "k" to x^2 will move the point (x, x^2) to the point (x, x^2+k), which will be above the previous point by k units.
If k is subtracted, instead of added, then the point will be moved downward.
The blanks are supposed to be filled with <u> positive </u>, and <u> negative </u>.
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<em>Comment on the question</em>
The wording of the statement you're completing is a bit odd. If k is negative (-2, for example), this statement is saying the graph is translated down -2 units. It is not. It is translated down |-2| = 2 units. The direction of translation depends on the sign of k. The amount of translation depends on the magnitude of k.
If you thoroughly understand (x, y) coordinates and how they are plotted on a graph, it should be no mystery that changing the y-coordinate will change the vertical position of the graph.
