3 years ago

20 points!!!!!!! Determine the rational roots of 2x^5 - 11x^4 + 14x^3 - 2x^2 + 12x + 9 = 0.

1 answer:

7 0

I would show you how i got it but unfortunately it's too much work. but the answers are

x = -1/2, 3, <span>±i

God bless!</span>

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How to factor 2n^2+3n-9 without splitting the middle term

kozerog [31]

$2n^2+3n-9= \\\\ a=2 \\ b=3 \\ c=-9 \\\\ \Delta= 3^2-4*2*(-9)=9+72\to\boxed{81} \\\\ x_1;x_2=\frac{-3 +\-\sqrt{81}}{2*2}= \frac{-3+/- 9}{4} \\\\ x_1=\frac{-3+9}{4}=\frac{6}{4}\to\boxed{\frac{3}{2}} \\\\ x_2=\frac{-3-9}{4}=\frac{-12}{4}\to\boxed{-4} \\\\ 2n^2+3n-9=(x-\frac{3}{2})(\x+4)$