You figure out how long it would take a car traveling at 25 mph
to cover 360 ft. Any driver who does it in less time is speeding.
(25 mi/hr) · (5,280 ft/mile) · (1 hr / 3,600 sec)
= (25 · 5280 / 3600) ft/sec = (36 and 2/3) feet per second.
To cover 360 ft at 25 mph, it would take
360 ft / (36 and 2/3 ft/sec) = 9.82 seconds .
Anybody who covers the 360 feet in less than 9.82 seconds
is moving faster than 25 mph.
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If you're interested, here's how to do it in the other direction:
Let's say a car covers the 360 feet in ' S ' seconds.
What's the speed of the car ?
(360 ft / S sec) · (1 mile / 5280 feet) · (3600 sec/hour)
= (360 · 3600) / (S · 5280) mile/hour
= 245.5 / S miles per hour .
The teacher timed one car crossing both strips in 7.0 seconds.
How fast was that car traveling ?
245.5 / 7.0 = 35.1 miles per hour
Another teacher timed another car that took 9.82 seconds to cross
both strips. How fast was this car traveling ?
245.5 / 9.82 = 25 miles per hour
First bring all terms in 'a' to the left side of the formula by subtracting ac from both sides
ab - ac - cd = ac - ac
ab - ac - cd = 0
now add cd to both sides
ab - ac -cd + cd = cd
ab - ac = cd
now factor the left side by taking out the 'a'
a(b-c) = cd
now divide both sides by (b-c)
a = cd / (b-c)
done
Answer:
wht cube
Step-by-step explanation:
Answer:
A system of the equation of a circle and a linear equation
A system of the equation of a parabola and a linear equation
Step-by-step explanation:
Let us verify our answer
A system of the equation of a circle and a linear equation
Let an equation of a circle as 
..........(1)
Let a liner equation Y = x ............(2)
substitute (2) in (1)
so Y = 
so the two solution are ( 
)
A system of the equation of a parabola and a linear equation
Let equation of Parabola be 
and linear equation y = x
substitute
Y = 0,1
so the two solutions will be (0,0) and (1,1)
Answer:
The numbers are 2 , 4 , 6 or 6 , 4 , 2
Step-by-step explanation:
For solution kindly refer to the attachment .
<u>Related</u><u> </u><u>Information</u><u> </u><u>:</u><u>-</u><u> </u>
• The sum of n terms of an AP is ,
=> S = n/2 [ 2a + ( n - 1 ) d ]
• The nth term of an AP is ,
=> T_n = a + ( n - 1 ) d
