Answer:
P(≥ 7 males) = 0.0548
Step-by-step explanation:
This is a binomial probability distribution problem.
We are told that Before 1918;
P(male) = 40% = 0.4
P(female) = 60% = 0.6
n = 10
Thus;probability that 7 or more were male is;
P(≥ 7 males) = P(7) + P(8) + P(9) + P(10)
Now, binomial probability formula is;
P(x) = [n!/((n - x)! × x!)] × p^(x) × q^(n - x)
Now, p = 0.4 and q = 0.6.
Also, n = 10
Thus;
P(7) = [10!/((10 - 7)! × 7!)] × 0.4^(7) × 0.6^(10 - 7)
P(7) = 0.0425
P(8) = [10!/((10 - 8)! × 8!)] × 0.4^(8) × 0.6^(10 - 8)
P(8) = 0.0106
P(9) = [10!/((10 - 9)! × 9!)] × 0.4^(9) × 0.6^(10 - 9)
P(9) = 0.0016
P(10) = [10!/((10 - 10)! × 10!)] × 0.4^(10) × 0.6^(10 - 10)
P(10) = 0.0001
Thus;
P(≥ 7 males) = 0.0425 + 0.0106 + 0.0016 + 0.0001 = 0.0548
Answer:
Step-by-step explanation:
1 and 2 are vertical angles
I think we're not supposed to do more than 3 problems in one answer; certainly not five pages. Does the 1/3 mean there are 10 more to come?
I'll do the first page.
6)
Right triangle, opposite side of 10, adjacent side of 21,
tan x = opp/adj = 10/21
x = arctan 10/21 = 25.46°
Answer: 25
7)
cos x = adj / hyp = 10/14
x = arccos 10/14 = 44.42°
Answer: 44
8)
tan x = opp/adj = 12/24 = 1/2
x = arctan 1/2 = 26.57°
Answer: 27
9)
tan x = 31/32
x = arctan 31/32 = 44.09°
Answer: 44
10)
x = arctan 10/27 = 20.32°
Answer: 20
Answer:
D 0.00000256
Step-by-step explanation:
Answer:
Step-by-step explanation:
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