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lianna [129]
2 years ago
11

What is the square root of -372

Mathematics
2 answers:
wel2 years ago
4 0

Answer:

19.2873015 (Done by a calculator) <---- could be wrong

Step-by-step explanation:

And fun fact:

Negative numbers don't have real square roots since a square is either positive or 0. The square roots of numbers that are not perfect square are members of irrational numbers. This means that they can't be written as the quotient of two integers.

Hope it helps!

Viktor [21]2 years ago
3 0

Answer:

No real solution

Step-by-step explanation:

you cannot take the square root of a negative number, because a negative times a negative is always a positive. (In later math, you will learn there are imaginary numbers which can be the square roots of negative numbers, but that's way in the future of math classes.)

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Peregrine falcons are known for their maneuvering ability. In a tight circular turn, a falcon can attain a centripetal accelerat
melomori [17]

Answer:

whats the qeustion sir ?

Step-by-step explanation:

i am confusion

4 0
2 years ago
How would you solve this? help.
Eddi Din [679]

Answer:

<em>Center: (3,3)</em>

<em>Radius: </em>2\sqrt{5}<em />

Step-by-step explanation:

<u>Midpoint and Distance Between two Points</u>

Given two points A(x1,y1) and B(x2,y2), the midpoint M(xm,ym) between A and B has the following coordinates:

\displaystyle x_m=\frac{x_1+x_2}{2}

\displaystyle y_m=\frac{y_1+y_2}{2}

The distance between both points is given by:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Point (5,7) is the center of circle A, and point (1,-1) is the center of the circle B. Given both points belong to circle C, the center of C must be the midpoint from A to B:

\displaystyle x_m=\frac{5+1}{2}=\frac{6}{2}=3

\displaystyle y_m=\frac{7-1}{2}=\frac{6}{2}=3

Center of circle C: (3,3)

The radius of C is half the distance between A and B:

d=\sqrt{(1-5)^2+(-1-7)^2}

d=\sqrt{16+64}=\sqrt{80}=\sqrt{16*5}=4\sqrt{5}

The radius of C is d/2:

r =4\sqrt{5}/2 = 2\sqrt{5}

Center: (3,3)

Radius: 2\sqrt{5}

8 0
3 years ago
How do you solve this inequality; 1/3x&gt;-2?
Kisachek [45]
1/3x>-2=1>3x.-2
=1>-6x
=-1/6>x
4 0
2 years ago
(2x2 − 5x)(4x2 − 12x + 10)<br><br> multiply
frez [133]
Is this 2x to the power of 2?
if it is then this is easy
list it out (just to show you how its solved)
2x^2*4x^2
2x^2*(-12x)
2x^2*10
then list the other one
-5x*<span>4x2
</span>-5x*(-12x)
-5x*10
so the whole answer is
8x^4+(-24x^3)+(-20x^3)+20x^2+60x^2+(-50x)
7 0
3 years ago
Read 2 more answers
If -(x - 1) = 5, find the value of -4x. Show your work.<br> PLEASEEEE !!!
irakobra [83]

Answer: x=-4

Step-by-step explanation:

1. Simplify:

-(x-1)=5 => -x+1=5

Isolate x:

-x=5-1 => -x=4 => x=-4

7 0
2 years ago
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