Question

Find the distance between (1, 3) and (-2, -6) and put it in simplest radical form

Answer 1

Answer:

$D=\sqrt{90}\ or\ D=9.49$

Step-by-step explanation:

$D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\\\D=\sqrt{(-2-1)^2+(-6-3)^2}\\\\D=\sqrt{(-2-1)^2+(-6-3)^2} \\\\D=\sqrt{(-3)^2+(-9)^2} \\\\D=\sqrt{9+81} \\\\D=\sqrt{90}\\\\D=9.49$

Hope this helps!

Answer 2

Answer:

• $\tt 9.48$

Step-by-step explanation:

(1,3) and (-2,-6)

$\tt Distance= \sqrt{(-6-3)^2+(-2-1)^2}$

$\tt =\sqrt{9^2+3^2}$

$\tt =\sqrt{81+9} =\sqrt{90}$

$\tt Distance=\sqrt{90} =9.48$