We have the following system:
y = -2x + 5
3x-4y = 2
Substituting y in equation 2 we have:
3x-4 (-2x + 5) = 2
We clear x:
3x + 8x - 20 = 2
11x = 2 + 20
x = 22/11
x = 2
Then, we substitute x = 2 in equation 1:
y = -2 (2) +5
y = -4 + 5
y = 1
Answer:
The solution to the system of equations is:
x = 2
y = 1

6 0

4 years ago

The quotient of x2 +x-6 ÷x2-6x +5<br><img src="https://tex.z-dn.net/?f=%7Bx%7D%5E%7B2%7D%20%20%2B%20x%20-%206%20%5Cdiv%20%20%7Bx

nataly862011 [7]

I think it's (2x-5+12/xx^3)

7 0

4 years ago

Read 2 more answers

6-1 reteach solving systems by graphing

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