Ask question

Ask question

All categories

3 years ago

11

Suppose you have a standard deck of 52 cards. What is the probability that if you select a card at random that it does not have

a face value of 3?
Round your answer to two decimal places.

1 answer:

dimaraw [331]3 years ago

8 0

I have no idea if i’m honest

You might be interested in

A model ship is built to a scale of 1 cm : 5m. The length of the model is 25 cm. What is the length of the actual ship?

Anestetic [448]

Answer:

<em>The length of the actual ship is 125 meters.</em>

Step-by-step explanation:

<u>Scaling</u>

Objects can be represented in a reduced or augmented size by using scaling which is basically multiplying or dividing by a constant factor. We use scaling for example, when representing geographic locations on a map.

A model ship is built to a scale of 1 cm: 5 m. This means that each centimeter of the model represents an actual length of 5 m.

The length of the model is 25 cm, thus the real ship has a length of 25*5 = 125 m.

The length of the actual ship is 125 meters.

7 0

3 years ago

Location is known to affect the number, of a particular item, sold by an auto parts facility. Two different locations, A and B,

Mama L [17]

We have two samples, A and B, so we need to construct a 2 Samp T Int using this formula:

$\displaystyle \overline {x}_1 - \overline {x}_2 \ \pm \ t^{*} \sqrt{\frac{s_1^2}{n_1} + \frac{s_2^2}{n_2} }$

In order to use t*, we need to check conditions for using a t-distribution first.

Random for both samples -- NOT STATED in the problem ∴ <u><em>proceed with caution</em></u>!
Independence for both samples: 130 < all items sold at Location A; 180 < all items sold at Location B -- we can reasonably assume this is true
Normality: CLT is not met; <u>n < 30</u> for both locations A and B ∴ <u><em>proceed with caution</em></u>!

<u>Since 2/3 conditions aren't met, we can still proceed with the problem but keep in mind that the results will not be as accurate until more data is collected or more information is given in the problem.</u>

<u>Solve for t*:</u>

<u></u>

We need the <u>tail area </u>first.

$\displaystyle \frac{1-.9}{2}= .05$

Next we need the <u>degree of freedom</u>.

The degree of freedom can be found by subtracting the degree of freedom for A and B.

The general formula is df = n - 1.

df for A: 13 - 1 = 12
df for B: 18 - 1 = 17
df for A - B: |12 - 17| = 5

Use a calculator or a t-table to find the corresponding <u>t-score for df = 5 and tail area = .05</u>.

t* = -2.015

Now we can use the formula at the very top to construct a confidence interval for two sample means.

$\overline {x}_A=39$
$s_A=8$
$n_A=13$
$\overline {x}_B = 55$
$s_B=2$
$n_B=18$
$t^{*}=-2.015$

Substitute the variables into the formula: $\displaystyle \overline {x}_1 - \overline {x}_2 \ \pm \ t^{*} \sqrt{\frac{s_1^2}{n_1} + \frac{s_2^2}{n_2} }$ .

$39-55 \ \pm \ -2.015 \big{(}\sqrt{\frac{(8)^2}{13} +\frac{(2)^2}{18} } } \ \big{)}$

Simplify this expression.

$-16 \ \pm \ -2.015 (\sqrt{5.1453} \ )$
$-16 \ \pm \ 3.73139$

Adding and subtracting 3.73139 to and from -16 gives us a confidence interval of:

$(-20.5707,-11.4293)$

If we want to <u>interpret</u> the confidence interval of (-20.5707, -11.4293), we can say...

<u><em>We are 90% confident that the interval from -20.5707 to -11.4293 holds the true mean of items sold at locations A and B.</em></u>

5 0

1 year ago

G(x)= 1296×<br> X= -1.75

vladimir2022 [97]

Answer:

- 2,268

Step-by-step explanation:

$g(x) = 1296x \\ plugging \: x = - 1.75 \\ g( - 1.75) = 1296 \times ( - 1.75) \\ = - 2,268 \\$

7 0

3 years ago

Graph the equation 3x+3y=−15 using the intercepts.

tatyana61 [14]

Answer:

To find the intercepts, equate one variable to

0

and solve for the other variable:

y-intercept

Set

x

to

0

and solve for

y

giving:

3

x

−

5

y

=

15

becomes:

(

3

⋅

0

)

−

5

y

=

15

0

−

5

y

=

15

−

5

y

=

15

−

5

y

−

5

=

15

−

5

−

5

y

−

5

=

−

3

y

=

−

3

or

(

0

,

−

3

)

x-intercept

Set

y

to

0

and solve for

x

giving:

3

x

−

5

y

=

15

becomes:

3

x

−

(

5

⋅

0

)

=

15

3

x

−

0

=

15

3

x

=

15

3

x

3

=

15

3

3

x

3

=

5

x

=

5

or

(

5

,

0

)

Next. we can plot the two points on the grid:

graph{((x-5)^2+(y)^2-0.125)((x)^2+(y+3)^2-0.125)=0 [-20, 20, -10, 10]}

Then, draw a line through the two points:

graph{(3x - 5y -15)((x-5)^2+(y)^2-0.125)((x)^2+(y+3)^2-0.125)=0 [-20, 20, -10, 10]}

7 0

2 years ago

Sharon serves the volleyball with an upward velocity of 23 ft/s. The ball is 3.5 ft above the ground when struck. How long does

BARSIC [14]

Answer:

,mkmm,..

Step-by-step explanation:

7 0

3 years ago