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Alexxandr [17]
2 years ago
14

Please help me with this math question, I'm so confused, I will mark you brainliest

Mathematics
1 answer:
kap26 [50]2 years ago
8 0

Answer:

A) 2

B) 3

C) -2

D) -1

Step-by-step explanation:

All you need to do is trace the given X value to the graph of the function after 'o' in (fog) or (gof). This is the same as finding the value of f(x) or g(x). After finding the value, make that value your x and trace to the new value on the other graph

a) Tracing -1 to y = f(X) gives y= 3. Tracing x =3 to g(x) gives 2

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puteri [66]

Answer:

58

Step-by-step explanation:

The median in a box plot is the line in the middle of the box

The median is 58

7 0
3 years ago
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Determine whether a triangle can be formed with the given side lengths. If so, use Heron's formula to find the area of the trian
kipiarov [429]
Triangle inequality rule states that the sum of eachpair of sides must be greater than the third sides.
 240 + 123 > 207 true
240 + 207 > 123 true
123 + 207 > 240 true

A = √(s(s-a)(s-b)(s-c))
s is the semi-perimeter (a + b + c)/2
s = (240 + 123 + 207)/2
s = 285
A = √(285*(285-249)(285-123)(285-207))
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4 0
3 years ago
PLEASE ANSWER THIS IS REALLY IMPORTANT!!!
Elan Coil [88]
Answer: C
Explanation: The y-intercept which is -9 matches with the equation and the slope matches too
4 0
3 years ago
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Flow meters are installed in urban sewer systems to measure the flows through the pipes. In dry weatherconditions (no rain) the
ziro4ka [17]

Answer:

a) \frac{(8)(30.23)^2}{20.09} \leq \sigma^2 \leq \frac{(8)(30.23)^2}{1.65}

363.90 \leq \sigma^2 \leq 4430.80

Now we just take square root on both sides of the interval and we got:

19.08 \leq \sigma \leq 66.56

b) For this case we are 98% confidence that the true deviation for the population of interest is between 19.08 and 66.56

Step-by-step explanation:

423.6, 487.3, 453.2, 402.9, 483.0, 477.7, 442.3, 418.4, 459.0

Part a

The confidence interval for the population variance is given by the following formula:

\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}

On this case we need to find the sample standard deviation with the following formula:

s=sqrt{\frac{\sum_{i=1}^8 (x_i -\bar x)^2}{n-1}}
And in order to find the sample mean we just need to use this formula:
[tex]\bar x =\frac{\sum_{i=1}^n x_i}{n}

The sample deviation for this case is s=30.23

The next step would be calculate the critical values. First we need to calculate the degrees of freedom given by:

df=n-1=9-1=8

The Confidence interval is 0.98 or 98%, the value of \alpha=0.02 and \alpha/2 =0.01, and the critical values are:

\chi^2_{\alpha/2}=20.09

\chi^2_{1- \alpha/2}=1.65

And replacing into the formula for the interval we got:

\frac{(8)(30.23)^2}{20.09} \leq \sigma^2 \leq \frac{(8)(30.23)^2}{1.65}

363.90 \leq \sigma^2 \leq 4430.80

Now we just take square root on both sides of the interval and we got:

19.08 \leq \sigma \leq 66.56

Part b

For this case we are 98% confidence that the true deviation for the population of interest is between 19.08 and 66.56

4 0
3 years ago
Use this picture to solve for X
Zepler [3.9K]

Answer:

x=2

Step-by-step explanation:

i would set up a system of equation using the pythagorean theorem:

1^2+x^2=z^2

4^2+x^2=y^2

Add up these equations to get:

17+2x^2=y^2+z^2

But notice that

y^2+z^2=5^2

So you can substitute

17+2x^2=25

2x^2=8

x^2=4

x=2

:)

8 0
2 years ago
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