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Ratling [72]
3 years ago
7

Between which two numbers will you find 5.634 x 10^2? A. 0.0562 and 0.0563B. 0.0563 and 0.0564C. 562 and 563D. 563 and 564

Mathematics
2 answers:
padilas [110]3 years ago
7 0

\\ \sf\bull\longmapsto 5.634\times 10^2

\\ \sf\bull\longmapsto 5634\times +0^{-3}\times 10^2

\\ \sf\bull\longmapsto 5634\times 10^{-1}

\\ \sf\bull\longmapsto 563.4

It will lie between 563 and 564

Xelga [282]3 years ago
7 0

Answer:

Hey ian !

<u>Answer</u><u>:</u><u> </u><u>D</u><u>.</u><u> </u><u>5</u><u>6</u><u>3</u><u> </u><u>and</u><u> </u><u>5</u><u>6</u><u>4</u>

\dashrightarrow \: { \tt{5.634 \times  {10}^{2} = 563.4 }}

• Therefore:

{ \tt{563 < 563.4 < 564}}

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The quotient when \frac{5-x}{x^2+3x-4} /\frac{x^2-2x - 15}{x^2+5x+4} in simplified form is \frac{-(x+1)}{(x-1)(x+3)}

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more numbers and variables.

Given that equation:

\frac{5-x}{x^2+3x-4} /\frac{x^2-2x - 15}{x^2+5x+4}

=\frac{5-x}{(x+4)(x-1)} /\frac{(x-5)(x+3)}{(x+4)(x+1)} \\\\=\frac{5-x}{(x+4)(x-1)} * \frac{(x+4)(x+1)}{(x-5)(x+3)}\\\\\frac{-(x-5)}{(x+4)(x-1)} * \frac{(x+4)(x+1)}{(x-5)(x+3)}\\\\=\frac{-(x+1)}{(x-1)(x+3)}

The quotient when \frac{5-x}{x^2+3x-4} /\frac{x^2-2x - 15}{x^2+5x+4} in simplified form is \frac{-(x+1)}{(x-1)(x+3)}

Find out more on equation at: brainly.com/question/2972832

#SPJ1

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