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givi [52]
3 years ago
12

PLS HELP.

Mathematics
2 answers:
Kisachek [45]3 years ago
3 0

Answer:

$(q-3p)

Step-by-step explanation:

1 book cost: $p

3 books cost:$p×3=$3p

Amount paid: $q

amount of change he will receive=$(q-3p)

NikAS [45]3 years ago
3 0

Answer:

Q - P

Step-by-step explanation:

I think that is what it is, it is my blank answer but i think it is that because he pays the cashier $Q and the book is $P, we know Daniel the big fat nerd wants to buy the book so he has enough (obviously)

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3-2/3b=1/3b-7 can you solve this
Sholpan [36]

3 - 2b/3 = b/3 - 7

3+7 = b/3 +2b/3

10 = 3b/3

b = 10


4 0
4 years ago
What is an example equivalent to <br> 9(5x-7y+4z) that results from using the distributive property
shepuryov [24]

Answer:

45x - 63 y + 36 z

Step-by-step explanation:

When I think of the distributive property, I imagine giving the outside term to everyone on the inside (multiplying).

9 (5x - 7y + 4z)

= 9 (5x) + 9 (-7y) + 9 (4z)

= 45x - 63 y + 36 z

Good luck with your math!

6 0
3 years ago
Solve the proportion. Please explain how you managed to get the answer! I don't know how to get there!
belka [17]
All you need to do is cross multiply and then solve for x
\frac{8}{x+9} =  \frac{2}{x-3}  \\ 8(x-3)=2(x+9) \\ 8x-24=2x+18 \\ 6x-24=18 \\ 6x=42 \\ x=7
3 0
3 years ago
Read 2 more answers
There are 5 days on a week, ally has 40 shirts. How many weeks will it take to wear all of her shirts?
Romashka-Z-Leto [24]
5 x 40 = 200 it will take her 200 days to wear each shirt
4 0
4 years ago
Read 2 more answers
Tienes un triángulo equilátero con lados de 10cm, lo divides en dos partes de manera horizontal tal que el área de ambos figuras
Tanya [424]

Answer:

x = 10/√2 ≈ 7.07

Step-by-step explanation:

Comenzaremos por dividir el triángulo en dos partes y definir H, como en la figura adjunta.

Aplicando el teorema de Tales, sabemos que:

\dfrac{l/2}{H}=\dfrac{x/2}{h}\\\\\\\dfrac{l}{H}=\dfrac{x}{h}

También sabemos que, dado que el tirángulo menor es la mitad que el triángulo mayor, la relación entre áreas es:

\dfrac{A}{A_x}=\dfrac{lH/2}{xh/2}=\dfrac{lH}{xh}=2

Dado que formamos dos triángulos rectángulos, podemos despejar el valor de H como:

(l/2)^2+H^2=l^2\\\\H^2=l^2-(l/2)^2=10^2-5^2=100-25=75\\\\H^2=\sqrt{75}

Podemos entonces despejar x de la siguiente manera:

h=\dfrac{H}{l}\cdot x=\dfrac{lH}{2x}\\\\\\2x^2\dfrac{H}{l}=lH\\\\\\2x^2=l^2\\\\\\x=\dfrac{l}{\sqrt{2}}=\dfrac{10}{\sqrt{2}}\approx7.07

6 0
4 years ago
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