Given that f(x)=5x^3+ax^2-4x-2 and that (x-1) is a factor of f(x), find a.
1 answer:
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Answer:
i)D:
ii)R:
iii) Y-int:(0,-1)
Step-by-step explanation:
i) The given absolute value function is;
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The absolute value function is defined for all real values of x.
The domain is all real numbers.
ii) The range is all y-values that will make x defined.
The given function,
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has vertex at, (-2,-3) and opens upwards.
This implies that, the minimum y-value is -3.
The range is
iii) To find the y-intercept substitute x=0 in to the function.
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.
.
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The y-intercept is (0,-1)
See attachment for graph.
