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MatroZZZ [7]
3 years ago
7

Given that f(x)=5x^3+ax^2-4x-2 and that (x-1) is a factor of f(x), find a.

Mathematics
1 answer:
stepladder [879]3 years ago
5 0

Answer:

a=1

Step-by-step explanation:

Because x-1 is factor of f(x)

for x1=1, f(1)=0, then

f(1)=5*1^3+a*1^2-4*1-2=0

5*1+a*1-4-2=0

5+a-6=0

a-1=0

a=1

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So we can use the Pythagorean's Theorem to figure this out.

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