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Wittaler [7]
2 years ago
6

Click this link to view O*NET’s Tasks section for Farmworkers and Laborers, Crop.

Computers and Technology
1 answer:
dangina [55]2 years ago
6 0

Answer:

B. operating tractors and machinery

D. maintaining vehicles and equipment

E. operating irrigation (watering) equipment

F. harvesting fruits and vegetables by hand

Explanation:

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The most common size for a brochure is _____.
Juli2301 [7.4K]
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3 years ago
Anybody remember that football game that everyone used to play during school
fiasKO [112]

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Like an actual video game or the one where you would play during recess then get in trouble when someone got hurt

Explanation:

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What device connects a lan's switch to the next network? qizzlets?
laila [671]
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2 years ago
What is JavaScript? JavaScript is a _____ language.
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JavaScript is a dynamic computer language. Hope this helps! (•‿•)

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2 years ago
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What is the size of the program counter for an avr that has a 1 kbyte rom capacity?
horsena [70]

Answer:

9 bits

Explanation:

 We all recognize 1 K bytes as =1024 bytes.  

And the storage medium used for program instructions are the non-volatile flash memories. The MCUs are always 8 bits, and a piece of the instructions revenues two or one 16-bit words. Besides we know program memory magnitude through the device name, and as an instance, the ATmega64x line emanates with 64KB of flash, and the ATmega32x line emanates with 32 KB. And there is nobody like off-chip program memory, and all of the codes that are being implemented by the AVR essentially be on the on-chip flash. However, this restraint is not ever applied to the AT94 FPSLIC AVR/FPGA chips. Also, you must know that AVR is a family of microcontrollers established by ATEL in 1996. It is a Harvard architecture type single-chip 8-bit RISC microcontroller. And it is supposed to be the first microcontroller which applied flash memory for storing the program They are heavily used in embedded systems.  

1k byte = 1024 bytes, However, if the program instruction takes 16 bits.  

And hence it only wishes 512.  

Here and now 512 = 10^9, and henceforth you necessitate 9 bits at minimum.  

excluding you can somehow paginate that (such as through one-bit pagination, you will be necessitating only 8 bits and so on.)  

Therefore the answer here = 9 bits.

5 0
3 years ago
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