What is the distance between (-1,-2) and (3,-1)

1 answer:

4 0

Answer:

d = √17

Step-by-step explanation:

d = √[(x₂ - x₁)² + (y₂ - y₁)²]

d = √[(3 - (-1))² + (-1 - (-2))²]

d = √4² + 1²

d = √16 + 1

d = √17

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