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CaHeK987 [17]
3 years ago
8

One subtacted from the product of 4 and a number is 11​

Mathematics
2 answers:
Sonja [21]3 years ago
7 0

I HOPE IT WILL HELP YOU.

Thank you.

^ - ^

Gala2k [10]3 years ago
5 0

Answer:

3

Step-by-step explanation:

4 x 3 = 12

12 - 1 = 11

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Help please thanks so much
Bas_tet [7]

Answer:

True

Step-by-step explanation:

because is it asking that the hight (y) is in what place in a more spicific wording

7 0
3 years ago
You read 9.75 pages in your science book and 24.5pages of a play for English class. It takes you 1.2minutes to read each page of
drek231 [11]

Answer:

the number of time spend in reading is 31.3 minutes

Step-by-step explanation:

The computation of the number of time spend in reading is as follows:

= 9.75 pages in science book × 1.2 minutes + 24.5 pages in english class × 0.8 minutes

= 11.7 minutes + 19.6 minutes

= 31.3 minutes

Hence, the number of time spend in reading is 31.3 minutes

The same is relevant and considered

6 0
3 years ago
Please help solve last one
mr_godi [17]

Answer:

The answer would be 7(2x+3y+z) or 7(2x+3y+1z) (both would be considered as correct)

Step-by-step explanation:


5 0
3 years ago
So this should be one of the last few ones
sergeinik [125]

Answer:

A

Step-by-step explanation:

Because you have to use the Pythagorean theorem to solve for this.

8 0
3 years ago
Consider rolling two fair dice one 3-sided the other 5-sided
Ne4ueva [31]

Since the dice are fair and the rolling are independent, each single outcome has probability 1/15. Every time we choose

1\leq x\leq 3,\quad 1\leq y \leq 5

We have P(X=x)=\frac{1}{3} and P(Y=y)=\frac{1}{5}, because the dice are fair.

Now we use the assumption of independence to claim that

P(X=x, Y=y) = P(X=x)\cdot P(Y=y) =\dfrac{1}{3}\cdot\dfrac{1}{5} = \dfrac{1}{15}

Now, we simply have to count in how many ways we can obtain every possible outcome for the sum. Consider the attached table: we can see that we can obtain:

  • 2 in a unique way (1+1)
  • 3 in two possible ways (1+2, 2+1)
  • 4 in three possible ways
  • 5 in three possible ways
  • 6 in three possible ways
  • 7 in two possible ways
  • 8 in a unique way

This implies that the probabilities of the outcomes of W=X+Y are the number of possible ways divided by 15: we can obtain 2 and 8 with probability 1/15, 3 and 7 with probability 2/15, and 4, 5 and 6 with probabilities 3/15=1/5

8 0
3 years ago
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