Answer:
D
Step-by-step explanation:
They didn't provide the number for one of the faces btw..
Answer:
V = 567 ft³
Step-by-step explanation:
V = Bh
<em>[note: a capital 'B' represents the </em><em>area</em><em> of the base] </em>
<em />
The right triangle is the triangular prism's base.
Because the triangle's height (9 ft) and it's base are the same value (9 ft), we can solve to find the area.
- We can identify the base easily because the base and the top of the prism are exactly the same shape
Area of triangular base:
A = 
A = 
(9 ⋅ 9)
A = (81)
A = 40.5
We have 'B' for the triangular prism's formula, so next we need 'h'. 14 ft is provided as the prism's height, so we just need to multiply 40.5 and 14 for our answer.
Volume of triangular prism:
V = Bh
V = (40.5)(14)
V = 567 ft³
Answer:
I think its 2nd one
HOPE IT HELPS, BE SAFE! Brainiest if possible pls! :)
2x2-5x-18=0
Two solutions were found :
x = -2
x = 9/2 = 4.500
Step by step solution :
Step 1 :
Equation at the end of step 1 :
(2x2 - 5x) - 18 = 0
Step 2 :
Trying to factor by splitting the middle term
2.1 Factoring 2x2-5x-18
The first term is, 2x2 its coefficient is 2 .
The middle term is, -5x its coefficient is -5 .
The last term, "the constant", is -18
Step-1 : Multiply the coefficient of the first term by the constant 2 • -18 = -36
Step-2 : Find two factors of -36 whose sum equals the coefficient of the middle term, which is -5 .
-36 + 1 = -35
-18 + 2 = -16
-12 + 3 = -9
-9 + 4 = -5 That's it
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -9 and 4
2x2 - 9x + 4x - 18
Step-4 : Add up the first 2 terms, pulling out like factors :
x • (2x-9)
Add up the last 2 terms, pulling out common factors :
2 • (2x-9)
Step-5 : Add up the four terms of step 4 :
(x+2) • (2x-9)
Which is the desired factorization
Equation at the end of step 2 :
(2x - 9) • (x + 2) = 0
Step 3 :
Theory - Roots of a product :
3.1 A product of several terms equals zero.
When a product of two or more terms equals zero, then at least one of the terms must be zero.
We shall now solve each term = 0 separately
In other words, we are going to solve as many equations as there are terms in the product
Any solution of term = 0 solves product = 0 as well.
