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Vladimir [108]
3 years ago
7

Four times y to the fourth power

Mathematics
2 answers:
alexandr1967 [171]3 years ago
8 0
(x 2 y) 4 = x2*4 y 1*4  = x 8 y4 
cluponka [151]3 years ago
5 0
4{ y }^{ 4 }\\ \\ ={ y }^{ 4 }+{ y }^{ 4 }+{ y }^{ 4 }+{ y }^{ 4 }\\ \\ =4\left( y\cdot y\cdot y\cdot y \right)
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X + x/3 = 4/9<br> solve for x!!
Lorico [155]

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x=1/3

Step-by-step explanation:

6 0
1 year ago
The vertices of a quadrilateral in the coordinate plane are known how can the perimeter of the figure be found
natta225 [31]

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6 0
3 years ago
Please help !!
S_A_V [24]

Answer:

The top right graph.

Step-by-step explanation:

5 0
3 years ago
Solve for q 2/3=-1/3q
tensa zangetsu [6.8K]
Q in (-oo:+oo)

2/3 = (1/3)*q // - (1/3)*q
                                                                  
2/3-((1/3)*q) = 0                                             
                                                                       ddddddddd
                                                                       d              d      
                                                                       d              d
(-1/3)*q+2/3 = 0                                              d              d
                                                                       d              d
2/3-1/3*q = 0 // - 2/3                                       d              d
                                                                       d              d
-1/3*q = -2/3 // : -1/3                                       d              d
                                                                       d              d
q = -2/3/(-1/3)                                    ddddddd               dddddddd     
                                                     dd                                               dd
q = 2                                            dd                                                 dd
                                                    dd                   dddd                      dd
q = 2                                              dddddddddd          dddddddddddd
6 0
2 years ago
Find the parabola whose minimum is at (−12,−2)(−12,−2) rather than the point given in the book. the parabola's equation is y=x2+
Hoochie [10]
The vertex form of the equation of a parabola is given by

y-k=a(x-h)^2

where (h, k) is the vertex of the parabola.

Given that the vertex of the parabola is (-12, -2), the equation of the parabola is given by

y-(-2)=a(x-(-12))^2 \\  \\ y+2=a(x+12)^2=a(x^2+24x+144)=ax^2+24ax+144a \\  \\ y=ax^2+24ax+114a-2 \\  \\ y=x^2+24x+ \frac{114a-2}{a}

For a = 1,

y=x^2+24x+112

<span>The parabola whose minimum is at (−12,−2) is given by the equation y=x^2+ax+b, where a = 24 and b = 112.</span>
8 0
3 years ago
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