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3 years ago

Four times y to the fourth power

Mathematics

2 answers:

alexandr1967 [171]3 years ago

8 0

(x 2 y) 4 = x2*4 y 1*4 = x 8 y4

cluponka [151]3 years ago

5 0

$4{ y }^{ 4 }\\ \\ ={ y }^{ 4 }+{ y }^{ 4 }+{ y }^{ 4 }+{ y }^{ 4 }\\ \\ =4\left( y\cdot y\cdot y\cdot y \right)$

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The event planner wants to put a podium at one of the foci. Which describes where the podium could be located relative to the ce

zimovet [89]

From the coordinate plane, the podium that could be located relative to the center will be B. 288 feet west.

<h3>Coordinate plane</h3>

From the complete information, there is a park in Washington and the event planner plots the park on a coordinate plane.

The table contains points along the perimeter of the park. Since the event planner wants to put a podium at one of the foci, the point where the podium could be located relative to the center will be 288 feet west.

Learn more about coordinate plane on:

brainly.com/question/13854649

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2 years ago

Solve the equation 2+3/4(2a-2)=8

jok3333 [9.3K]

Answer:

A=5 hope this works

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

In the figure below, m2 1=(x-12)° and mZ2 =5xº.<br> Find the angle measures.

erma4kov [3.2K]

Answer:

15 165

Step-by-step explanation:

m1 + m2 = 180

x-18 +5x = 180

6x = 198

x = 33

m1 = 15

m2 = 165

6 0

2 years ago

Find the m please it’s due today . (-11,5) & (2,-4)

d1i1m1o1n [39]

Answer:

m = $\frac{-9}{13}$

Step-by-step explanation:

I'm assuming by m, you mean the slope.

You have two points. (-11, 5) and (2, -4)

m = change in y-value ÷ change in x-value

1) Substitute in the points.

m = $\frac{(-4)- 5}{2 - (-11)}$

2) Solve.

-4 - 5 = -9

2 - (-11) = 13

So, the slope would equal $\frac{-9}{13}$ .

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3 years ago

Find the equation of the line containing the points (20,-7) and (10,-2). Type your answer in this order and don't use spaces or

aliina [53]

$(\stackrel{x_1}{20}~,~\stackrel{y_1}{-7})\qquad (\stackrel{x_2}{10}~,~\stackrel{y_2}{-2}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{-2}-\stackrel{y1}{(-7)}}}{\underset{run} {\underset{x_2}{10}-\underset{x_1}{20}}}\implies \cfrac{-2+7}{-10}\implies -\cfrac{1}{2}$

$\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-7)}=\stackrel{m}{-\cfrac{1}{2}}(x-\stackrel{x_1}{20}) \\\\\\ y+7=-\cfrac{1}{2}x+10\implies y=-\cfrac{1}{2}x+3$

4 0

2 years ago