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2 years ago

I need help please!! Can someone help me please

Mathematics

1 answer:

Talja [164]2 years ago

5 0

Answer:

The pictures is unclear resend again.

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F the simple interest on $4000 for 6 years is $1440, then what is the interest rate?

Alborosie

Answer:

Step-by-step explanation:

$rate=\frac{interest \times 100}{principle \times time } \\=\frac{1440 \times 100}{4000 \times 6 } \\=6 \%$

7 0

2 years ago

A teacher's assistant entered 10 scores into the online gradebook in

-Dominant- [34]

Answer:

Ok I got it it’s 50

Step-by-step explanation:

because To divide by

, multiply by its reciprocal, 5.

10÷

= 105

= 50

8 0

2 years ago

Write a function g whose graph represents a reflection in the x-axis of the graph of f(x)= -5x+2

Rudiy27

Answer:

Step-by-step explanation:

4 0

3 years ago

tia_tia [17]

$\bf \qquad \qquad \textit{ratio relations}
\\\\
\begin{array}{ccccllll}
&Sides&Area&Volume\\
&-----&-----&-----\\
\cfrac{\textit{similar shape}}{\textit{similar shape}}&\cfrac{s}{s}&\cfrac{s^2}{s^2}&\cfrac{s^3}{s^3}
\end{array} \\\\
-----------------------------\\\\
\cfrac{\textit{similar shape}}{\textit{similar shape}}\qquad \cfrac{s}{s}=\cfrac{\sqrt{s^2}}{\sqrt{s^2}}=\cfrac{\sqrt[3]{s^3}}{\sqrt[3]{s^3}}\\\\
-------------------------------\\\\$

$\bf \cfrac{smaller}{larger}\qquad \cfrac{s^2}{s^2}=\cfrac{18}{32}\implies \left( \cfrac{s}{s} \right)^2=\cfrac{18}{32}\implies \cfrac{s}{s}=\sqrt{\cfrac{18}{32}}
\\\\\\
\cfrac{s}{s}=\cfrac{\sqrt{18}}{\sqrt{32}}\implies \cfrac{s}{s}=\cfrac{\sqrt{9\cdot 2}}{\sqrt{16\cdot 2}}\implies \cfrac{s}{s}=\cfrac{\sqrt{3^2\cdot 2}}{\sqrt{4^2\cdot 2}}\implies \cfrac{s}{s}=\cfrac{3\sqrt{2}}{4\sqrt{2}}
\\\\\\
\cfrac{s}{s}=\cfrac{3}{2}$

6 0

3 years ago

Find the area of the region enclosed by the curves yequals

Step2247 [10]

The area enclosed by the given 2 curves is; 8/3 or 2.67

<h3>How to Solve Integration with Limits?</h3>

We want to find the area enclosed by the curves;

y = x² - 2x

y = -x² + 2x

The point of intersection of the parabola and the line is given by;

x² - 2x = -x² + 2x

2x² - 4x = 0

Solving this gives;

x = 0, 2

Therefore, the area bounded by the parabola and the line between x = 0 and x = 2 is given as;

A = ∫₀² (-x² + 2x - x² + 2x)

A = ∫₀² (-2x² + 4x)

Using online integration calculator here gives;

A = 2.67

Read more about Integration at; brainly.com/question/14388434

#SPJ1

6 0

1 year ago