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Shalnov [3]
3 years ago
15

I need to find the answer

Mathematics
1 answer:
scoundrel [369]3 years ago
8 0

Answer:

39/8= 4 7/8

Step-by-step explanation:

You might be interested in
Two consecutive odd numbers total -20 find the smaller
Yakvenalex [24]

Answer:

-9

Step-by-step explanation:

use an equation to solve this

consecutive means in succession, one after the other

since they're odd, both numbers have to be odd

let x be the first number

x+x+2=-20

+2 because if you only +1, one of the numbers would be even

2x+2=-20

-2. -2

2x=-22

x=-11

the smaller would be -9 since we are adding x and x+2 together

6 0
2 years ago
Pls help due tonight, I just found the assignment !<br> Will give brainly for the correct answer
Alex777 [14]

Answer:

1) slope is -1/3

2) slope is 3 or 3/1

3)slope is -3/2

4)slope is3/2

5)slope is 5/3

6)slope is 7/3

Step-by-step explanation:

6 0
3 years ago
Write the equation of the line f(3)=6 and f(8)=10
LuckyWell [14K]
F(x)=y
so
f(3)=6 and f(8)=10
the points are
(x,y)
(3,6)
(8,10)

y=mx+b
m=slope
b=yintercept

to find the slope between 2 points, (x1,y1) and (x2,y2)
the slope is (y2-y1)/(x2-x1)
(3,6)
(8,10)
slope=(10-6)/(8-3)=4/5

y=4/5x+b
find b


the equation for a line with slope m and a pointn on it is (x1,y1) is
y-y1=m(x-x1)

a point is (3,6)
y-6=4/5(x-3)
y-6=4/5x-12/5
add 6 or 30/5
y=4/5x+18/5
3 0
3 years ago
please solve it please solve it please solve it please solve it please solve it please solve it please solve it please solve it
katovenus [111]

Since \alpha and \beta are roots of ax^2+bx+c, we can factorize the quadratic in terms of the roots as

ax^2+bx+c = a(x-\alpha)(x-\beta)

Expanding the right side gives

ax^2+bx+c = ax^2-a(\alpha+\beta)x+a\alpha\beta

so that

\alpha + \beta = -\dfrac ba \\\\ \alpha\beta = \dfrac ca

A polynomial with roots \alpha^2 and \beta^2 would be

(x-\alpha^2)(x-\beta^2)

and expanding this gives

x^2 - (\alpha^2+\beta^2)x+\alpha^2\beta^2

Now,

\alpha\beta = \dfrac ca \implies \alpha^2\beta^2 = (\alpha\beta)^2 = \dfrac{c^2}{a^2}

and

(\alpha+\beta)^2 = \alpha^2 + 2\alpha\beta + \beta^2 \\\\ \implies \alpha^2+\beta^2 = \left(-\dfrac ba\right)^2 -2\left(\dfrac ca\right) = \dfrac{b^2-2ac}{a^2}

So we can write the second quadratic in terms of a,b,c as

(x-\alpha^2)(x-\beta^2) = x^2 - \dfrac{b^2-2ac}{a^2}x + \dfrac{c^2}{a^2}

and to make things look cleaner, scale the whole expression by a^2 to get

\boxed{a^2x^2 + (2ac-b^2)x + c^2}

4 0
3 years ago
Suppose y varies directly with x. If y = 4 when x = -2, find x when y = 6.
daser333 [38]

Answer:

Step-by-step explanation:

3 0
3 years ago
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