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ehidna [41]
3 years ago
13

Item 4

Mathematics
1 answer:
trasher [3.6K]3 years ago
4 0

Answer:

<-4

Step-by-step explanation:

2x+3<-5

2x+3-3<-5-3

2x<-8

2x/2<-8/2

x<-4

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2 Points
SOVA2 [1]

A

distributive property

-4x - y + 2x - 6y

Combine like terms

-2x - 7y

6 0
4 years ago
Read 2 more answers
Can someone please help me with this
sweet-ann [11.9K]

Answer:

(D) 29.3

Step-by-step explanation:

The answer is all the days added together and then divided by 10.

20+30+40+38+25+22+39+22+26+31=293.

293/10=29.3

3 0
2 years ago
Xanthe and Sarah do some fundraising for their local nursing home. Together they raised $$$302. If Xanthe raised $$$102 more tha
Dimas [21]

Given :

Xanthe and Sarah together raised $302 .

If Xanthe raised $102 more than Sarah .

To Find :

The amount raised by Sarah .

Solution :

Let , amount raise by Sarah is x .

So , by the relation given , price raised by Xanthe is 102 + x .

Now , sum of their amount raised is :

x+(x+102)=302\\\\2x=302-102\\\\x=\$100

Therefore , the amount raised by Sarah is $100 .

Hence , this is the required solution .

6 0
3 years ago
I don’t understand how to do this.
kherson [118]
I believe the answer to be only sequence A.
-Hope this helps, have a nice day! :)
3 0
3 years ago
Read 2 more answers
7. Write an equation for the line that is parallel to the given line and that passes through the given point.
Vlad1618 [11]

Answer:

C. y = 1/2x - 14

Step-by-step explanation:

Find the slope of the original line and use the point-slope formula  y − y 1 = m ( x − x 1 )  to find the line parallel to  y = 1 /2 x − 8 .

y = 1 /2 x − 14                              PARALLEL

...................................................................................................................................................

Find the negative reciprocal of the slope of the original line and use the point-slope formula  y − y 1 = m ( x − x 1 )  to find the line perpendicular to  y = 1 /2 x − 8 .

y = − 2 x − 29                               PERPENDICULAR

8 0
3 years ago
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