6-2x=6x-10x+20 solve for x
combine like terms and get all to the same side of equation
6-2x+10x-6x=20
10x-2x-6x+6=20
8x=20-6
8x=14
x=14/8=7/4
Answer: L, J, K
Step-by-step explanation:
L, J, and K are collinear because they all lie on the same line.
<h3>
<u>Explanation</u></h3>
- Given the system of equations.
![y = - \frac{1}{4} x - 2 \\ x = 4](https://tex.z-dn.net/?f=y%20%3D%20%20-%20%20%5Cfrac%7B1%7D%7B4%7D%20x%20-%202%20%20%5C%5C%20x%20%3D%204)
- Substitute x = 4 in the first equation.
![y = - \frac{1}{4} (4) - 2 \\ y = - 1 - 2 \\ y = - 3](https://tex.z-dn.net/?f=y%20%3D%20%20-%20%20%5Cfrac%7B1%7D%7B4%7D%20%284%29%20-%202%20%5C%5C%20y%20%3D%20%20-%201%20-%202%20%20%5C%5C%20y%20%3D%20%20-%203)
We have both x and y values. Therefore, we can answer in coordinate point form.
<h3>
<u>Answer</u></h3>
<u>
</u>
Answer:
7
Step-by-step explanation:
Criteria:
• same number of books on each shelf
⇒find a number that divides 58 and 145
• greatest number of books on each shelf
⇒find the greatest number that divides 58 and 145
Find the GCF of 58 and 145.
58 = 2 ⋅ 29
145 = 5 ⋅ 29The GCF of 58 and 145 is 29.
Each shelf will contain 29 books.
There are 203 total books (because 58 + 145 = 203).
Divide 203 by 29 to find the number of shelves there should be.
203 / 29 = 7
Therefore, there will be 7 shelves.
we know that
The measurement of the exterior angle is the semi-difference of the arcs which comprises
In this problem
∠FGH is the exterior angle
∠FGH=![50\°](https://tex.z-dn.net/?f=50%5C%C2%B0)
∠FGH=
-----> equation A
![arc\ FEH+arc\ FH=360\°](https://tex.z-dn.net/?f=arc%5C%20FEH%2Barc%5C%20FH%3D360%5C%C2%B0)
--------> equation B
Substitute equation B in equation A
![100\°=(arc\ FEH-[360\°-arc\ FEH])](https://tex.z-dn.net/?f=100%5C%C2%B0%3D%28arc%5C%20FEH-%5B360%5C%C2%B0-arc%5C%20FEH%5D%29)
![100\°=2arc\ FEH-360\°](https://tex.z-dn.net/?f=100%5C%C2%B0%3D2arc%5C%20FEH-360%5C%C2%B0)
![2arc\ FEH=360\°+100\°](https://tex.z-dn.net/?f=2arc%5C%20FEH%3D360%5C%C2%B0%2B100%5C%C2%B0)
![arc\ FEH=230\°](https://tex.z-dn.net/?f=arc%5C%20FEH%3D230%5C%C2%B0)
therefore
<u>The answer is</u>
The measure of arc FEH is equal to ![230\°](https://tex.z-dn.net/?f=230%5C%C2%B0)