Answer:
we can not draw on here
Step-by-step explanation:
Hello:
<span>a system of two equations that has (1,5) as its only solution is :
</span>y-5=2(x-1)
y-5=3(x-1)
Answer:
1
Step-by-step explanation:
5C5
= 5! / (5! (5 - 5)!)
= 5! / 5! 0! (0! =1)
= 1/1
= 1
K, so since directix is below focus, it opens up (2<4)
and directix is y=something so equation is (x-h)^2+4p(y-k) where (h,k) is vertex and p is distance from focus to vertex. if it opens down, p<0, if it opens up, p>0
and the vertex is in the middle of the focus and directix
so
distance bewten (-2,4) and y=2 is 2 units
2/2=1, so 1 unit down from focus
vertex is in the middle so it is at (-2,3)
also, opens up so p=1
vertex (-2,3)
p=1
(x-(-2))^2=4(1)(y-3)
(x+2)^2=4(y-3) is an equation
Answer:
3. 0.594. 4. 0.568. 1. 0.532. 2. 0.332
