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kompoz [17]
3 years ago
10

Which ordered pairs make the open sentence true?

Mathematics
1 answer:
Hitman42 [59]3 years ago
8 0

Answer:

-2,1

Step-by-step explanation:

hope it will be helpful for i

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(a) What is a sequence? A sequence is an unordered list of numbers. A sequence is the sum of an ordered list of numbers. A seque
crimeas [40]

Step-by-step explanation:

A sequence is an ordered list of numbers.

lim n → ∞ an = 8 means that as n approaches infinity (becomes large), an approaches 8.

lim n → ∞ an = ∞ means that as n approaches infinity (becomes large), an approaches infinity (becomes large).

6 0
3 years ago
Drag the tiles to the correct boxes to complete the pairs.
erastova [34]

Answer:

√8 ==> 2 units, 2 units

√7 ==> √5 units, √2 units

√5 ==> 1 unit, 2 units

3 ==> >2 units, √5 units

Step-by-step explanation:

To determine which pair of legs that matches a hypotenuse length to create a right triangle, recall the Pythagorean theorem, which holds that, for a right angle triangle, the square of the hypotenuse (c²) = the sum of the square of each leg length (a² + b²)

Using c² = a² + b², let's find the hypotenuse length for each given pairs of leg.

=>√5 units, √2 units

c² = (√5)² + (√2)²

c² = 5 + 2 = 7

c = √7

The hypothenuse length that matches √5 units, √2 units is √7

=>√3 units, 4 units

c² = (√3)² + (4)²

c² = 3 + 16 = 19

c = √19

This given pair of legs doesn't match any given hypotenuse length

=>2 units, √5 units

c² = (2)² + (√5)²

c² = 4 + 5 = 9

c = √9 = 3

legs 2 units, and √5 units matche hypotenuse length of 3

=>2 units, 2 units

c² = 2² + 2² = 4 + 4

c² = 8

c = √8

Legs 2 units, and 2 units matche hypotenuse length of √8

=> 1 unit, 2 units

c² = 1² + 2² = 1 + 4

c² = 5

c = √5

Leg lengths, 1 unit and 2 units match the hypotenuse length, √5

3 0
3 years ago
Given the sequence in the table below, determine the sigma notation of the sum for term 4 through term 15.
Naya [18.7K]
It's a geometric sequence.

4,-12,36,... \\ \\
a_1=4 \\
r=\frac{a_2}{a_1}=\frac{-12}{4}=-3 \\ \\
a_n=a_1 \times r^{n-1} \\
a_n=4 \times (-3)^{n-1} \\
a_n=4 \times (-3)^{-1} \times (-3)^n \\
a_n=4 \times (-\frac{1}{3}) \times (-3)^n \\
a_n=-\frac{4}{3}(-3)^n

It's the sum for term 4 through term 15.

 \boxed{ \sum\limits_{n=4}^{15} (\frac{4}{3}(-3)^n)}
8 0
3 years ago
List at least five importance of having self discipline m following protocol during enhanced community quarantine in your respec
Maksim231197 [3]

Answer:

no clue -0- if I knew I would tell you

4 0
2 years ago
You want your markup to be 35% of the final selling price. Your cost is $200. For what price should you sell the product
Sidana [21]
B
Multiply 35% by 200 and get 70
Add that 70 to 200 and you’ll get B which is 270
5 0
2 years ago
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