Z-49+851=100+21z /////////////////////////////////////////////////
2 answers:
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Answer: C.-1.5
Step-by-step explanation:
Given: The burning time of a very large candle is normally distributed with mean of 2500 hours and standard deviation
of 20 hours.
Let X be a random variable that represent the burning time of a very large candle.
Formula:
For X = 2470
So, the z-score they corresponds to a lifespan of 2470 hours. =-1.5
Hence, the correct option is C.-1.5.