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Slav-nsk [51]
3 years ago
12

Help please hurry......

Mathematics
2 answers:
user100 [1]3 years ago
8 0

All multiples of 15 between 0 and 300,inclusive

How?

\\ \sf\longmapsto f(x)=15x

\\ \sf\longmapsto f(0)=15(0)=0

\\ \sf\longmapsto f(20)=15(20)=300

Hence.

\\ \sf\longmapsto 0\leqslant R_f\leqslant 300

aleksandr82 [10.1K]3 years ago
6 0

Answer:

<em><u>All multiples of 15 between 0 and 300,inclusive</u></em>

<em><u>All multiples of 15 between 0 and 300,inclusiveHow?</u></em>

⟼f(x)=15x

⟼f(0)=15(0)=0

⟼f(20)=15(20)=300

Hence,

⟼0⩽R f ⩽300.

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How does the graph of g(x) = 5x – 3 compare to the graph of f(x) = 5*?
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Answer:

the graph is shifted down 3 units

Step-by-step explanation:

5x-3

meaning the original graph of 5x going down three units

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3 years ago
Given a circle with a radius of 6, what the the length of an arc measuring 30 degrees
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\bf \textit{arc's length}\\\\&#10;s=\cfrac{\theta \pi r}{180}\quad &#10;\begin{cases}&#10;r=radius\\&#10;\theta =angle~in\\&#10;\qquad degrees\\&#10;------\\&#10;r=6\\&#10;\theta =30&#10;\end{cases}\implies s=\cfrac{30\cdot \pi \cdot 6}{180}\implies s=\pi
6 0
4 years ago
Jacob solves the system of equations by forming a matrix equation.
Lyrx [107]

Simultaneous equations can be solved using inverse matrix operation.

The complete steps of Jacob's solution are:

\left[\begin{array}{cc}4&1\\-2&3\end{array}\right]^{-1} \cdot \left[\begin{array}{cc}4&1\\-2&3\end{array}\right]\left[\begin{array}{c}x&y\end{array}\right] = \frac{1}{14}\left[\begin{array}{cc}3&-1\\2&4\end{array}\right] \cdot \left[\begin{array}{c}2&-22\end{array}\right]

\left[\begin{array}{c}x&y\end{array}\right] = \left[\begin{array}{cc}4&1\\-2&3\end{array}\right] \cdot \left[\begin{array}{c}2&-22\end{array}\right]

\left[\begin{array}{c}x&y\end{array}\right] = \frac{1}{14} \left[\begin{array}{c}28&-84\end{array}\right]

\left[\begin{array}{c}x&y\end{array}\right] = \left[\begin{array}{c}2&-6\end{array}\right]

We have:

4x + y = 2

-2x + 4y = -22

Calculate the determinant of \left[\begin{array}{cc}4&1\\-2&3\end{array}\right]

|A| = 4 \times 3 -1 \times -2

|A| = 12 +2

|A| = 14

So, the inverse matrix becomes

A = \frac{1}{14}\left[\begin{array}{cc}4&1\\-2&3\end{array}\right]

Replace the first column with \left[\begin{array}{c}2&-22\end{array}\right] to calculate the value of x

x = \frac{1}{14}\left[\begin{array}{cc}2&1\\-22&3\end{array}\right]

So, we have:

x = \frac{1}{14}(2 \times 3 - 1 \times -22)

x = \frac{1}{14}(6 +22)

x = \frac{1}{14}(28)

x = 2

Replace the second column with \left[\begin{array}{c}2&-22\end{array}\right] to calculate the value of y

y = \frac{1}{14}\left[\begin{array}{cc}4&2\\-2&-22\end{array}\right]

So, we have:

y = \frac{1}{14}(4 \times -22 - 2 \times -2)

y = \frac{1}{14}(-88 +4)

y = \frac{1}{14}(-84)

y = -6

Hence, the complete process is:

\left[\begin{array}{cc}4&1\\-2&3\end{array}\right]^{-1} \cdot \left[\begin{array}{cc}4&1\\-2&3\end{array}\right]\left[\begin{array}{c}x&y\end{array}\right] = \frac{1}{14}\left[\begin{array}{cc}3&-1\\2&4\end{array}\right] \cdot \left[\begin{array}{c}2&-22\end{array}\right]

\left[\begin{array}{c}x&y\end{array}\right] = \left[\begin{array}{cc}4&1\\-2&3\end{array}\right] \cdot \left[\begin{array}{c}2&-22\end{array}\right]

\left[\begin{array}{c}x&y\end{array}\right] = \frac{1}{14} \left[\begin{array}{c}28&-84\end{array}\right]

\left[\begin{array}{c}x&y\end{array}\right] = \left[\begin{array}{c}2&-6\end{array}\right]

Read more about matrices at:

brainly.com/question/11367104

6 0
3 years ago
Jennifer had 7/8 foot board she cut off 1/4 foot peice that was for a project.in feet how much board was left?
guapka [62]

\frac{5}{8} \text{ feet board is left }

<em><u>Solution:</u></em>

Given that, Jennifer had 7/8 foot board she cut off 1/4 foot peice that was for a project

To find: Board that was left

From given,

\text{Total length of board } =\frac{7}{8} \text{ feet }

\text{Foot that was cut off } = \frac{1}{4} \text{ feet }

Remaining feet of board is found by finding the difference between total length of board and foot that was cut off

\text{Reamining board } = \text{Total length of board - feet of board that was cut off}\\

Substituting the values we get,

\text{Remaining board } = \frac{7}{8} - \frac{1}{4}\\\\\text{Remaining board } =\frac{7}{8} - \frac{1 \times 2}{4 \times 2}\\\\\text{Remaining board } =\frac{7}{8} -\frac{2}{8} = \frac{7-2}{8}\\\\\text{Remaining board } =\frac{5}{8}

Thus \frac{5}{8} feet board is left

5 0
3 years ago
Find the measure of the missing angles. need help ASAP
pochemuha
Sorry if it’s confusing i tried color coding it

the measure of angle 6 is 71.5 degrees

3 0
3 years ago
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