kinematics allows to find the kinetic variables and the relationships between position, speed and acceleration, for launching projectiles we can find:
a) The horizontal velocity vₓ = 2.1 m/s
b) The height of the table y₀= 0.60 m
given parameters
- Time to reach the floor t = 0.35 s
- Horizontal distance x = 0.75 m
to find
a. Horizontal speed
b. table height
Let's use the kinematics relations, let's start by defining a reference frame with the x-axis along the motion of the ball and the vertical y-axis with the positive direction up.
We look for the initial velocity in the x axis, there is no acceleration we can use the uniform kinematic relations
vₓ = x / t
Where vx is the horizontal velocity, g the acceleration of gravity (g=9.8 m/s²) and t the time
vₓ = 0.75 / 0.35
vₓ = 2.14 m / s
We look for the height of the table that corresponds to the initial height (y₀) of the ball, when reaching the floor the height is zero, on the vertical axis the initial velocity is zero (v_{oy} = 0)
y = y₀ + v_{oy} t - ½ g t²
0 = y₀ + 0 - ½ g t²
y₀ = ½ g t²
y₀ = ½ 9.8 0.35²
y₀i = 0.60 m
- In conclusion with the kinematic relations for the launch of projectiles we can find the horizontal velocity vₓ = 2.1 m / s and the height of the table i = 0.60 m
learn more about projectile launch here:
brainly.com/question/12792922
