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steposvetlana [31]
4 years ago
13

Which of the following might be the material list for an experiment?

Physics
1 answer:
Alisiya [41]4 years ago
8 0

Answer:

C

Explanation:

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7. If 8 million kg of water flows over Niagara Falls each second, calculate the power available at the bottom of the falls.
Alexxx [7]

Answer:

The power will be "3.92×10⁹ Watts". A further explanation is given below.

Explanation:

The given values as per the question,

Rate,

= 8 million kg

Distance,

= 50 m

Gravity,

= 9.8 m/s²

As we know,

The power will be:

⇒ Power = Rate\times Distance\times  Gravity

On putting the values, we get

⇒             =  8\times 10^6\times 50\times 9.8

⇒             =3.92\times 10^9 \  Watts

7 0
3 years ago
Daily life examples of pressure of solids on solids?​
Ipatiy [6.2K]

Explanation:

There's a massive amount, just think of anything everyday. Like a table on the floor, or when your walking around and putting pressure on the floor. When you squeeze something which is solid. Anything like that will do.

6 0
3 years ago
The left end of a rod of length and rotational inertia is attached to a frictionless horizontal surface by a frictionless pivot,
natima [27]

Answer:

See explaination

Explanation:

please kindly see attachment for the step by step solution of the given problem.

6 0
3 years ago
Which ecosystem has the most biodiversity? How do you<br> know?
Bezzdna [24]

Answer:

ecosystem B

Explanation:

because it goes through more animal's and is correct

8 0
3 years ago
d. e. Study the given diagram and calculate the following: i. work done by load ii. work done by effort iii. M.A iv. V.R v. effi
il63 [147K]

i. The work done by the load is load x distance moved by load.

ii. The work done by effort is effort applied x distance moved by effort.

iii. The mechanical advantage of the simple machine is Load/effort.

iv. The velocity ratio of the simple machine is 2.

v. The efficiency of the machine is M.A/V.R x 100%.

<h3>Work done by the load</h3>

The work done by the load is the product of the load and the distance through which the load is moved. The magnitude is calculated as follows;

Work done by the load = load x distance moved by load

<h3>Work done by effort</h3>

The work done by the effort is the product of the effort and the distance through which the effort is applied. The magnitude is calculated as follows;

Work done by effort = effort applied x distance moved by effort

<h3>Mechanical advantage of the simple machine</h3>

M.A = Load/Effort

<h3>Velocity ratio of the simple machine</h3>

V.R = distance moved by effort / distance moved by load

V.R  = 30 cm/15 cm

V.R = 2

<h3>Efficiency of the machine</h3>

E = (M.A/V.R) x 100%

Thus, the work done by the load is load x distance moved by load.

The work done by effort is effort applied x distance moved by effort.

The mechanical advantage of the simple machine is Load/effort.

The velocity ratio of the simple machine is 2.

The efficiency of the machine is M.A/V.R x 100%.

Learn more about mechanical advantage here: brainly.com/question/25984831

#SPJ1

4 0
2 years ago
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