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sweet [91]
3 years ago
11

I have to write two ratios that are equivalent to 1:1

Mathematics
2 answers:
velikii [3]3 years ago
3 0

Answer:

2:2 and 4:4

Step-by-step explanation:

Anything with identical numbers basically.

Zolol [24]3 years ago
3 0

   <u><em>I have to write two ratios that are equivalent to 1:1         </em></u>  

                       

                                          I Hate Math......

In mathematics, a ratio is a relationship between two numbers that indicates how many times the first number contains the second. Put another way, a ratio says how much of one thing there is compared to another thing.

We can express ratios in different ways.

a) We Use the the symbol : to separate the values. For instance:

4:1

b) We can use the word to. For instance:

3 to 1  

c) We can write it like a fraction. For instance:

__________________________________________

Since the problem establishes to write two ratios that are equivalent to 1:1. From the Figure below there is 1 red square to 1 blue square. So, writing the new ratios we have:  

Step-by-step explanation: First.  

2:2 is equivalent to 1:1, that is the ratio is also 1 red square to 1 blue square, even though there are more squares. You can see this in the Figure below.

Second.  

4:4 is equivalent to 1:1. As in the previous statement the ratio is also 1 red square to 1 blue square, even though there are four red squares and four blue squares as illustrated in the Figure.

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3 0
4 years ago
[6+4=10 points] Problem 2. Suppose that there are k people in a party with the following PMF: • k = 5 with probability 1 4 • k =
kirza4 [7]

Answer:

1). 0.903547

2). 0.275617

Step-by-step explanation:

It is given :

K people in a party with the following :

i). k = 5 with the probability of $\frac{1}{4}$

ii). k = 10 with the probability of $\frac{1}{4}$

iii). k = 10 with the probability $\frac{1}{2}$

So the probability of at least two person out of the 'n' born people in same month is  = 1 - P (none of the n born in the same month)

= 1 - P (choosing the n different months out of 365 days) = 1-\frac{_{n}^{12}\textrm{P}}{12^2}

1). Hence P(at least 2 born in the same month)=P(k=5 and at least 2 born in the same month)+P(k=10 and at least 2 born in the same month)+P(k=15 and at least 2 born in the same month)

= \frac{1}{4}\times (1-\frac{_{5}^{12}\textrm{P}}{12^5})+\frac{1}{4}\times (1-\frac{_{10}^{12}\textrm{P}}{12^{10}})+\frac{1}{2}\times (1-\frac{_{15}^{12}\textrm{P}}{12^{15}})

= 0.25 \times 0.618056 + 0.25 \times 0.996132 + 0.5 \times 1

= 0.903547

2).P( k = 10|at least 2 share their birthday in same month)

=P(k=10 and at least 2 born in the same month)/P(at least 2 share their birthday in same month)

= $0.25 \times \frac{0.996132}{0.903547}$

= 0.0.275617

6 0
3 years ago
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