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2 years ago

PLEASE HELP Here is an equation. P = d(4 + tg) What is the equation when solved for g?

Mathematics

2 answers:

elena55 [62]2 years ago

7 0

Answer:

g = p/dt - 4/t

Step-by-step explanation:

Have a nice day!

and please ask if you have any questions.

igor_vitrenko [27]2 years ago

6 0

Answer:The equation when solved for g is ---->g=P/dt - 4/t

Step-by-step explanation:

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3 years ago

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3 years ago

2x+y=8 y+3z=5 z+2w=1 5w+3x=9 Find the solution to each variable

morpeh [17]

Answer:

w = 0, x = 3, y = 2, z = 1

Step-by-step explanation:

You can use each equation to write an expression that will substitute into the next equation.

y = 8 -2x . . . . from the first equation

8 -2x + 3z = 5 . . . . . substituted into the second equation

z = (-3 +2x)/3 . . . . . solved for z

(-1 +2/3x) +2w = 1 . . . . . substituted into the third equation

w = (2 -2/3x)/2 . . . . . solved for w

5(1 -1/3x) +3x = 9 . . . . . substituted into the last equation

4/3x = 4 . . . . . simplified, 5 subtracted

x = 3 . . . . . . . . multiply by 3/4

w = 0 . . . . . . . .value of x substituted into equation for w

z = 1 . . . . . . . . value of x substituted into equation for z

y = 2 . . . . . . . .value of x substituted into equation for y

The solution is (w, x, y, z) = (0, 3, 2, 1).

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3 years ago

For every integer k from 1 to 10, inclusive the "k"th term of a certain sequence is given by (−1)(k+1)∗(12k). If T is the sum of

Katena32 [7]

Answer:

Option D. is the correct option.

Step-by-step explanation:

In this question expression that represents the kth term of a certain sequence is not written properly.

The expression is $(-1)^{k+1}(\frac{1}{2^{k}})$ .

We have to find the sum of first 10 terms of the infinite sequence represented by the expression given as $(-1)^{k+1}(\frac{1}{2^{k}})$ .

where k is from 1 to 10.

By the given expression sequence will be $\frac{1}{2},\frac{(-1)}{4},\frac{1}{8}.......$

In this sequence first term "a" = $\frac{1}{2}$

and common ratio in each successive term to the previous term is 'r' = $\frac{\frac{(-1)}{4}}{\frac{1}{2} }$

r = $-\frac{1}{2}$

Since the sequence is infinite and the formula to calculate the sum is represented by

$S=\frac{a}{1-r}$ [Here r is less than 1]

$S=\frac{\frac{1}{2} }{1+\frac{1}{2}}$

$S=\frac{\frac{1}{2}}{\frac{3}{2} }$

S = $\frac{1}{3}$

Now we are sure that the sum of infinite terms is $\frac{1}{3}$ .

Therefore, sum of 10 terms will not exceed $\frac{1}{3}$

Now sum of first two terms = $\frac{1}{2}-\frac{1}{4}=\frac{1}{4}$

Now we are sure that sum of first 10 terms lie between $\frac{1}{4}$ and $\frac{1}{3}$

Since $\frac{1}{2}>\frac{1}{3}$

Therefore, Sum of first 10 terms will lie between $\frac{1}{4}$ and $\frac{1}{2}$ .

Option D will be the answer.

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3 years ago

How to express 24 divided by the difference of 8 and 2

SSSSS [86.1K]

You can express it as 24 / (8-2)

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3 years ago