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alexdok [17]
2 years ago
7

Solve for x. -(-2-5x) + (-2) = 18 X=-90 X=-18/5 X=18/5 X=90

Mathematics
1 answer:
mash [69]2 years ago
6 0
Hope it helps I guesss

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John and Martha are contemplating having children, but John’s brother has galactosemia (an autosomal recessive disease) and Mart
Rina8888 [55]
<h2>Answer:</h2>

Probability=\frac{1}{24}

<h2>Step-by-step explanation:</h2>

As the question states,

John's brother has Galactosemia which states that his parents were both the carriers.

Therefore, the chances for the John to have the disease is = 2/3

Now,

Martha's great-grandmother also had the disease that means her children definitely carried the disease means probability of 1.

Now, one of those children married with a person.

So,

Probability for the child to have disease will be = 1/2

Now, again the child's child (Martha) probability for having the disease is = 1/2.

Therefore,

<u>The total probability for Martha's first child to be diagnosed with Galactosemia will be,</u>

Probability=\frac{2}{3}\times \frac{1}{2}\times \frac{1}{2}\times \frac{1}{4}\\Probability=\frac{1}{24}

(Here, we assumed that the child has the disease therefore, the probability was taken to be = 1/4.)

<em><u>Hence, the probability for the first child to have Galactosemia is \frac{1}{24}</u></em>

3 0
3 years ago
A student is trying to solve the system of two equations given below: Equation P: y + z = 6 Equation Q: 8y + 7z = 1 Which of the
Sergeeva-Olga [200]
<span>P:      y + z = 6
Q:  8y + 7z = 1

A. This makes y = -8Y which will eliminate the "y"'s when the equations are added.


</span>
4 0
3 years ago
Read 2 more answers
Use Stokes' Theorem to evaluate C F · dr F(x, y, z) = xyi + yzj + zxk, C is the boundary of the part of the paraboloid z = 1 − x
Serggg [28]

I assume C has counterclockwise orientation when viewed from above.

By Stokes' theorem,

\displaystyle\int_C\vec F\cdot\mathrm d\vec r=\iint_S(\nabla\times\vec F)\cdot\mathrm d\vec S

so we first compute the curl:

\vec F(x,y,z)=xy\,\vec\imath+yz\,\vec\jmath+xz\,\vec k

\implies\nabla\times\vec F(x,y,z)=-y\,\vec\imath-z\,\vec\jmath-x\,\vec k

Then parameterize S by

\vec r(u,v)=\cos u\sin v\,\vec\imath+\sin u\sin v\,\vec\jmath+\cos^2v\,\vec k

where the z-component is obtained from

1-(\cos u\sin v)^2-(\sin u\sin v)^2=1-\sin^2v=\cos^2v

with 0\le u\le\dfrac\pi2 and 0\le v\le\dfrac\pi2.

Take the normal vector to S to be

\vec r_v\times\vec r_u=2\cos u\cos v\sin^2v\,\vec\imath+\sin u\sin v\sin(2v)\,\vec\jmath+\cos v\sin v\,\vec k

Then the line integral is equal in value to the surface integral,

\displaystyle\iint_S(\nabla\times\vec F)\cdot\mathrm d\vec S

=\displaystyle\int_0^{\pi/2}\int_0^{\pi/2}(-\sin u\sin v\,\vec\imath-\cos^2v\,\vec\jmath-\cos u\sin v\,\vec k)\cdot(\vec r_v\times\vec r_u)\,\mathrm du\,\mathrm dv

=\displaystyle-\int_0^{\pi/2}\int_0^{\pi/2}\cos v\sin^2v(\cos u+2\cos^2v\sin u+\sin(2u)\sin v)\,\mathrm du\,\mathrm dv=\boxed{-\frac{17}{20}}

6 0
3 years ago
The answer and how you got the answer
olasank [31]

Answer:

\frac{34}{15}

Step-by-step explanation:

we are asked to evaluate

4\tfrac{1}{4}÷1\tfrac{7}{8}

Above we are given mixed fraction which can be converted in proper fraction using formula given below

a\tfrac{b}{c}=\frac{a \times c +b}{c}

Hence

4\tfrac{1}{4}=\frac{4 \times 4 +1}{4}

4\tfrac{1}{4}=\frac{17}{4}

Also

1\tfrac{7}{8}=\frac{1 \times 8 +7}{8}

1\tfrac{7}{8}=\frac{15}{8}

Hence

4\tfrac{1}{4} ÷ 1\tfrac{7}{8}

can be written as

\frac{17}{4} ÷ \frac{15}{8}

Also we know the rule for dividing fraction is as given below

\frac{a}{b} ÷ \frac{c}{d} = \frac{a}{b} \times \frac{d}{c}

Hence

\frac{17}{4} ÷ \frac{15}{8} = \frac{17}{4} \times \frac{8}{15}

=\frac{17 \times 2}{15}

=\frac{34}{15}

8 0
3 years ago
A man drove his car a distance of 260 miles in 4 hours. If continuing at this rate is possible, he will travel ____ miles in 8 h
spayn [35]

Answer:

520 miles

Step-by-step explanation:

since 4 is half of 8, you just multiply 260 by 2.

4 0
3 years ago
Read 2 more answers
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