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Yuri [45]
3 years ago
5

Help againnn i hate matg

Mathematics
1 answer:
ser-zykov [4K]3 years ago
6 0

Hello User!

Correction "Math"

Answer: 12 4/7

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The vertex angle of an isosceles triangle measures 64 degrees. What is the measure of its base angles?
Dvinal [7]
So hmmm check the picture below

in an isosceles triangle, two sides are equal, and thus the angles those twin legs make, are also twin angles

let's say the angle made is "a", so all internal angles will be 64 + a + a = 180
or 64 + 2a = 180

thus 2a = 180 - 64 => 2a = 116, thus a = 116/2

7 0
3 years ago
Dave uses 500 milliliters of juice for a How many more punch recipe He mixes it with 2 liters of ' pears did she buy ginger ale
Yakvenalex [24]
1 liter: 1000 ml

so 2 liters: 2000 ml. s

so now the last step adding- 2000+500= 2500
 
so Dave made 2500 millimeters of punch

8 0
3 years ago
Help me please and ty
pav-90 [236]

Answer:                                                                                                                       3m

And I had to write something for this to be ong enough so thats what this is:)

3 0
3 years ago
Two automobiles left simultaneously from cities A and B heading towards each other and met in 5 hours. The speed of the automobi
quester [9]

Answer:

  450 km

Step-by-step explanation:

<u>Equations</u>

We can define 3 variables: a, b, d. Let "a" and "b" represent the speeds of the cars leaving cities A and B, respectively. Let "d" represent the distance between the two cities. We can write three equations in these three variables:

1. The relation between "a" and "b":

  a = b -10 . . . . . . . the speed of car A is 10 kph less than that of car B

2. The relation between speed and distance when the cars leave at the same time:

  d = (a +b)·5 . . . . . . distance = speed × time

3. Note that the time it takes car B to travel 150 km to the meeting point is (150/b). (time = distance/speed) The total distance covered is ...

  distance covered by car A in 4 1/2 hours + distance covered by both cars (after car B leaves) = total distance

  4.5a + (150/b)(a +b) = d

__

<u>Solution</u>

Substituting for d, we have ...

  4.5a + 150/b(a +b) = 5(a +b)

  4.5ab +150a +150b = 5ab +5b^2 . . . . . . multiply by b, eliminate parentheses

  5b^2 +0.5ab -150(a +b) = 0 . . . . . . . . . . subtract the left side

Now, we can substitute for "a" and solve for b.

  5b^2 + 0.5b(b-10) -150(b -10 +b) = 0

  5.5b^2 -5b -300b +1500 = 0 . . . . . . . . eliminate parentheses

  11b^2 -610b +3000 = 0 . . . . . . . . . . . . . multiply by 2

  (11b -60)(b -50) = 0 . . . . . . . . . . . . . . . . factor

The solutions to this equation are ...

  b = 60/11 = 5 5/11 . . . and . . . b = 50

Since b must be greater than 10, the first solution is extraneous, and the values of the variables are ...

  • b = 50
  • a = b-10 = 40
  • d = 5(a+b) = 5(90) = 450

The distance between A and B is 450 km.

_____

<u>Check</u>

<em>When the cars leave at the same time</em>, their speed of closure is the sum of their speeds. They will cover 450 km in ...

  (450 km)/(40 km/h +50 km/h) = 450/90 h = 5 h

__

<em>When car A leaves 4 1/2 hours early</em>, it covers a distance of ...

  (4.5 h)(40 km/h) = 180 km

before car B leaves. The distance remaining to be covered is ...

  450 km - 180 km = 270 km

When car B leaves, the two cars are closing at (40 +50) km/h = 90 km/h, so will cover that 270 km in ...

  (270 km)/(90 km/h) = 3 h

In that time, car B has traveled (3 h)(50 km/h) = 150 km away from city B, as required.

5 0
3 years ago
Read 2 more answers
the length of a rectangle is four times its width. if the perimeter of the rectangle is 60cm, what is the area?
Inessa [10]

Let, width = x

length = 4x

perimeter = 2(4x+x) = 60

10x = 60

x = 6

so, 4x = 24

Area would be: 24*6 = 144 cm²


7 0
3 years ago
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