Answer:
3. 150.72 in²
4. 535.2cm²
Step-by-step Explanation:
3. The solid formed by the net given in problem 3 is the net of a cylinder.
The cylinder bases are the 2 circles, while the curved surface of the cylinder is the rectangle.
The surface area = Area of the 2 circles + area of the rectangle
Take π as 3.14
radius of circle = ½ of 4 = 2 in
Area of the 2 circles = 2(πr²) = 2*3.14*2²
Area of the 2 circles = 25.12 in²
Area of the rectangle = L*W
width is given as 10 in.
Length (L) = the circumference or perimeter of the circle = πd = 3.14*4 = 12.56 in
Area of rectangle = L*W = 12.56*10 = 125.6 in²
Surface area of net = Area of the 2 circles + area of the rectangle
= 25.12 + 125.6 = 150.72 in²
4. Surface area of the net (S.A) = 2(area of triangle) + 3(area of rectangle)
= 
Where,
b = 8 cm
h = ![\sqrt{8^2 - 4^2} = \sqrt{48} = 6.9 cm} (Pythagorean theorem)w = 8 cm[tex]S.A = 2(0.5*8*6.9) + 3(20*8)](https://tex.z-dn.net/?f=%20%5Csqrt%7B8%5E2%20-%204%5E2%7D%20%3D%20%5Csqrt%7B48%7D%20%3D%206.9%20cm%7D%20%28Pythagorean%20theorem%29%3C%2Fp%3E%3Cp%3Ew%20%3D%208%20cm%3C%2Fp%3E%3Cp%3E%5Btex%5DS.A%20%3D%20%202%280.5%2A8%2A6.9%29%20%2B%203%2820%2A8%29)
Answer:
See below
Step-by-step explanation:
Use 5 for "x" or "a number" and see if the inequality is true.
a) =3 < 5+11 < 2 . . . . false. 16 is not less than 2
b) 7·5 ≥ 35 or 4·5 < -12 . . . . true. 35 = 35
c) -7 + 2·5 = 3 is at most 2 . . . . false. 3 > 2
d) 5·5 +3 = 28 is between 2 and 30 . . . . true.
Area de la base es un hexagono: Nota: asumiendo que 39 cm son el lado de un hexagono. Menuda pizza.
A = 3*sqrt(3)/2*a^2 = 3*sqrt(3)/2*39^2 = 3951.67391746839972 cm^2
Hay dos base y tapa, doble:
7903.34783493679944 cm^2
Luego los lados verticales:
6 * 39 * 4.7 = 1099.8 cm^2
TOtal = 9003.14783 = 9003.147 cm^2 = 9003.15 cm^2
It’s making me use 20 characters so here’s a lil text
The possibilities are:
bbbb
bbbg
bbgg
bggg
This shows that there is a 1 in 4 chance of having three boys and one girl
So the answer could be 1/4 or a 25% chance
