Start by assigning a variable name to the "number" -- call it x.
Now write out what they say:
"The product of 1/3 and the sum of a number and 3" -- that's 1/3 times x + 3, or (1/3)(x + 3) or (x + 3) / 3
It's "between negative one and five"
So that means:
-1 < (x + 3) / 3 < 5
So now solve this inequality. First multiply everything by 3.
-3 < x + 3 < 15
Subtract 3 from all the terms:
-6 < x < 12
So the answer is, all numbers between -6 and 12
Answer:
y=9
Step-by-step explanation:
4-2y+8=-6
-2y=-4-8-6
-2y=-18 divide by -2 both side
y=-18/-2
y=9
Answer:
Using z score formula:
X = z ∂ + µ
= 157.833
Step-by-step explanation:
Solution:
Mean = µ = 1262
Standard deviation = ∂ = 117
(a) 28th percentile for the number of chocolate chip.
P( z < z) = 28%
= 0.28
P( z<- 0.58) = 0.28
Z = -0.58
By using z score formula:
Z = x - µ /∂
-0.58= x – 117 / 1262
X = (- 0.58)(117) + (1262)
= 1194.14
(b) Middle 97% of bag.
P(-z < z < z) = 97%
= 0.97
P( z < z) – p(z < -z) = 0.97
2p(z < z) -1 = 0.97
2p (z < z) = 1 + 0.97
P(z < z) = 1.97 / 2
= 0.99
P(z < 2.33) = 0.99
Z ± 2.33
By using z score formula:
Z = x - µ / ∂
X = z ∂ + µ
= - 2.33 x 117 + 1262
=989.39
Z = 2.33
X = z ∂ + µ
= 2.33 x 117 + 1262
=1533.61
(c) What is the interquartile range of the number of chocolate chips in a bag of chocolate.
By using standard normal table,
The z dist’n formula:
P(z < z ) = 25%
=0.25
P(z < -0.6745) = 0.25
Z = 0.6745
Using z score formula:
X = z∂ + µ
= - 0.6745 x 117 + 1262
= 1183.0835
First quartile = Q1 =1183.0835
The third quartile is:
P(z<z) = 75%
= 0.75
P(z < 0.6745) = 0.75
Z = 0.6745
Using z score formula:
X = z ∂ + µ
= 0.6745 x 117 + 1262
= 1340.9165
IQR = Q3 – Q1
= 1340.9165 – 1183.0835
= 157.833
Answer: (0,0)
Step-by-step explanation: The domain of the expression is all real numbers except where the expression is undefines. In this case, there is no real number that makes the expression undefined.
Hope this helps you out. ☺
Answer:
3x+6 is the answer
Step-by-step explanation:
Have a good day and stay safe!
