You do the same operation on both sides.
Hope this helps!
Answer:
45 mph
Step-by-step explanation:
This is a really good question to know the answer to. It is tricky and a bit indirect (which means you have to find something else before you can find the speed of the car.)
Let's keep track of what he does in the time allotted.
How far does Joe go in 5 minutes? That's the amount of time he's on the road before she is.
convert 5 minutes into hours. 5 minutes * 1 hour / 60 minutes = 1/12 of an hour
d = r*t
r = 30 km/hour
t = 1/12 hour
d = 30 km/hr * 1/12 hour = 2.5 km
Now she's about to start. She wants to catch him in 10 minutes
d = r*t
r = x mph
t = 10 minutes = 10 minutes * 1 hour * 60 minutes = 1/6 of an hour.
How far does he go in the 10 minute time?
d = 30 * 1/6 = 5 km
What is his total distance
5 km + 2.5 km = 7.5 km
Finally how fast does she need to go to catch him
d = 7.5 km
r = ? This is what you are trying to find
t = 1/6 of an hour
d = r*t
7.5 km = r * (1/6)hour divide by 1/6 hour
7.5 km // 1/6 hour = r
r = 7.5 * 6 = 45 mph
Answer:
The transformation from ABC to A'B'C' is a reflection over y axis then a translation 10 units right.
A graph shows the solutions to be
(x, y) = (-6, 312) or (6, 312)To solve algebraically, remove a factor of 2 from the second equation and use that expression to substitute for y in the first equation.
10x^2 -(8x^2 +24) = 48
2x^2 = 72
x = ±√(72/2) = ±6
y = 8*36 +24 = 312
Answer:
1 inch = 2 feet
Step-by-step explanation:
