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Salsk061 [2.6K]
3 years ago
15

gabby's piggy bank contains dimes and nickels worth $6.40. If she has 84 coins in all, how many of each does she have?

Mathematics
1 answer:
Sergeu [11.5K]3 years ago
5 0
If we let Q be the number of quarters and N be number of nickels, this is the formula we would use:
[1] 25Q + 5N = 635 (using cents instead of dollars)


We also know something about Q and N.

[2] Q + N = 51


So multiply both sides of the second equation by 5. The reason we do this is because we're going to need to cancel out one of the variables (either Q or N) to solve for the other one. If we multiply times 5, we'll have 5N in both equations.
5Q + 5N = 255

Now we have two equations, and the second one can be subtracted from the first.

25Q + 5N = 635
-(5Q + 5N) = -255
---------------------
20Q = 380
so
Q = 19

There are 19 quarters.

And since there are 51 coins in all, 51-19 = 32 nickels.
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Answer: Reject the eight- ounces claim.

Step-by-step explanation:

For left tailed test , On a normal curve the rejection area lies on the left side of the critical value.

It means that if the observed z-value is less than the critical value then it will fall into the rejection region other wise not.

As per given ,

Objective : A coffee-dispensing machine is supposed to deliver eight ounces of liquid or less.

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the critical value for z for a one-tailed test with the tail in the left end is -1.645 and the obtained value is -1.87.

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F(x) = x2<br> What is f(x) + f(x) + f(x)?
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if you meant x squared the answer is 3x^2

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6 0
3 years ago
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The temperature fell from 0 Degrees Fahrenheit to 15 and one-half Degrees Fahrenheit below 0 in 5 and three-fourths hours. Wen t
Kryger [21]

Answer:

The correct answer will be:

-\dfrac{62}{23}

Step-by-step explanation:

It is given that :

Initial temperature, T_1 = 0^\circ F

Final temperature,

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Time taken :

5\dfrac{3}{4}\ hrs = \dfrac{5 \times 4+3}{4}\ hrs = \dfrac{23}{4}\ hrs

Change in temperature per hour:

\dfrac{\text{Difference of temperature}}{\text{Total Time Taken}}\\\Rightarrow \dfrac{T_2-T_1}{\text{Total Time Taken}}

Putting the values of temperatures and time:

\dfrac{\dfrac{-31}{2}-0}{\dfrac{23}{4}}\\\Rightarrow \dfrac{\dfrac{-31}{2}}{\dfrac{23}{4}}\\\Rightarrow \dfrac{-31 \times 4}{2 \times 23}} \text{---- Error done by Wen at this step}\\\Rightarrow \dfrac{-31 \times 2}{23}}\\\Rightarrow \dfrac{-62}{23}}

The error done by Wen was during calculating the values of fraction.

So, the correct answer is :\frac{-62}{23}} instead of \frac{-713}{8}

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4 years ago
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