Activity which odd number comes immedediatly before 87?

What is the answer to this question?<br> Y=x^2-1 with the input as 5

mixas84 [53]

We can see that, when the input is 5, the output is 24.

<h3>How to evaluate an equation?</h3>

Here we have the equation:

$y = x^2 - 1$

Where y is the output and x is the input.

We want to evaluate it with the input as 5, so we need to replace the variable x by the number 5, we will get:

$y = 5^2 - 1 = 24$

Then we can see that, when the input is 5, the output is 24.

If you want to learn more about evaluating functions:

brainly.com/question/1719822

#SPJ1

4 0

2 years ago

Please help with solving

Makovka662 [10]

N.O = 4
N is midpoint of M.0
Meaning M.N also has to be 4
4+4= 8
N.P = 6
0.P = 2
8+ 2 = 10

4 0

2 years ago

Subtract 7x^2−5xy+8y2 from −2x^2−15xy+9y^2

Digiron [165]

Answer

Subtract $7x^2 -5xy+8y^2$ from $-2x^2 -15xy+9y^2$

then;

$-2x^2 -15xy+9y^2 - (7x^2 -5xy+8y^2)$

Remove the bracket we have;

$-2x^2 -15xy+9y^2 - 7x^2 + 5xy - 8y^2$

Like terms are those terms which have same variable to the same power.

Combine like terms;

$-9x^2 -10xy+y^2$

Therefore, Subtracting $7x^2 -5xy+8y^2$ from $-2x^2 -15xy+9y^2$ we get $-9x^2 -10xy+y^2$

7 0

3 years ago

A circle has the equation 2x²+12x+2y²−16y−150=0.

KonstantinChe [14]

Answer: B. The coordinates of the center are (-3,4), and the length of the radius is 10 units.

Step-by-step explanation:

The equation of a circle in the center-radius form is:

$(x-h)^{2} +(y-k)^{2}=r^{2}$ (1)

Where $(h,k)$ are the coordinates of the center and $r$ is the radius.

Now, we are given the equation of this circle as follows:

$2x^{2}+12x+2y^{2}-16y-150=0$ (2)

And we have to write it in the format of equation (1). So, let's begin by applying common factor 2 in the left side of the equation:

$2(x^{2}+6x+y^{2}-8y-75)=0$ (3)

Rearranging the equation:

$x^{2}+6x+y^{2}-8y=75$ (4)

$(x^{2}+6x)+(y^{2}-8y)=75$ (5)

Now we have to complete the square in both parenthesis, in order to have a perfect square trinomial in the form of $(a\pm b)^{2}=a^{2}\pm+2ab+b^{2}$ :

<u>For the first parenthesis:</u>

$x^{2}+6x+b^{2}$

We can rewrite this as:

$x^{2}+2(3)x+b^{2}$

Hence in this case $b=3$ and $b^{2}=9$ :

$x^{2}+2(3)x+3^{2}=x^{2}+6x+9=(x+3)^{2}$

<u>For the second parenthesis:</u>

$y^{2}-8y+b^{2}$

We can rewrite this as:

$y^{2}-2(4)y+b^{2}$

Hence in this case $b=-3$ and $b^{2}=9$ :

$y^{2}-2(4)y+4^{2}=y^{2}-8y+16=(y-4)^{2}$

Then, equation (5) is rewritten as follows:

$(x^{2}+6x+9)+(y^{2}-8y+16)=75+9+16$ (6)

<u>Note we are adding 9 and 16 in both sides of the equation in order to keep the equality.</u>

Rearranging:

$(x-3)^{2}+(y-4)^{2}=100$ (7)

At this point we have the circle equation in the center radius form $(x-h)^{2} +(y-k)^{2}=r^{2}$

Hence:

$h=-3$

$k=4$

$r=\sqrt{100}=10$

8 0

3 years ago

Karen claps her hand and hears the echo from a distant wall 0.113 s later. How far away is the wall? The speed of sound in air i

insens350 [35]

Answer:

19.3795 m

Step-by-step explanation:

If sound travels at 343 m/s and it took Karen 0.113 s to hear the echo from the wall, the distance travelled by the sound is:

$D=343\frac{m}{s} *0.113\ s\\D= 38.759\ m$

Note that the distance calculated above is the distance travelled from Karen to the wall and then back from the wall to Karen. Therefore, the distance between Karen and the wall is:

$d=\frac{38.759}{2}\\d=19.3795\ m$

The wall is 19.3795 m away from Karen.

3 0

3 years ago

Activity which odd number comes immedediatly before 87?​

Activity which odd number comes immedediatly before 87?