Ok this is a very question that can solved very easily. So we know that there three numbers, and they are consecutive, this means that they are all one bigger than the number before so for example 1,2, and 3 or 20, 21, and 22. These numbers are called consecutive. Now let's just pretend that the answer to this question is the variable "x". Now x is the smallest number in all the three numbers.
Using our knowledge of consecutive numbers we can say that the next to numbers will be one more than the number before so:
(x+1) and (x+2)
So we have our three numbers: x , x+1 , and x+2. Now let's set these numbers equal to 177.
177 = x + x + 1 + x + 2 → Combine like terms.
177 = 3x + 3 → Subtract 3 from both sides.
174 = 3x → Divide both sides by 3
58 = x
So that means that our first and smallest number is going to be 58 our second number will be +1 so 59 and our third number will be +2 so 60.
So the three numbers will be 58, 59, and 60.
Hope this helped.
Answer:
let the daughter age be x
let mother age be 3x
Step-by-step explanation:
x+3x= 80
4x = 80
x= 80\4
x=20
daughter age is 20
mather age= 80 -20
= 60
daughter age 20
mother age 60
-10= ( -4)+(-3)+(-2)+(-1)
I:2x – y + z = 7
II:x + 2y – 5z = -1
III:x – y = 6
you can first use III and substitute x or y to eliminate it in I and II (in this case x):
III: x=6+y
-> substitute x in I and II:
I': 2*(6+y)-y+z=7
12+2y-y+z=7
y+z=-5
II':(6+y)+2y-5z=-1
3y+6-5z=-1
3y-5z=-7
then you can subtract II' from 3*I' to eliminate y:
3*I'=3y+3z=-15
3*I'-II':
3y+3z-(3y-5z)=-15-(-7)
8z=-8
z=-1
insert z in II' to calculate y:
3y-5z=-7
3y+5=-7
3y=-12
y=-4
insert y into III to calculate x:
x-(-4)=6
x+4=6
x=2
so the solution is
x=2
y=-4
z=-1
