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lozanna [386]
3 years ago
11

What is the range of f(x)=x2+4 if the domain is {2,0,1}

Mathematics
1 answer:
Bumek [7]3 years ago
3 0
F(x)=x2+4=2*2+4=4+4=8 when x=2
f(x)=x2+4=0*2+4=4 when x=0
f(x)=x2+4=1*2+4=6 when x=1
Have a nice day!!! ^^

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caleb has 7 black caps 4 yellow caps and 9 blue caps in his wardrobe. Two caps are drawn wothout replacement from the wardrobe.
Hitman42 [59]

Answer:

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Step-by-step explanation:

What is probability?

Probability is simply the chances of something occuring.

As a formula, I like to say that formula = # of favorable outcomes / total # of outcomes

Where favorable outcomes is what we want to happen and total # of outcomes is the total number of possibilities.

In order to find the probability of the occurrence of something in a row, we multiply the individual probabilities of each action

Understanding the question

Here we are given that caleb has 7 black caps 4 yellow caps and 9 blue caps in his wardrobe and given this we want to find the probability of Caleb randomly selecting 2 blue caps without replacing it the first being drawn.

So here # of favorable outcomes = # of blue caps = 9

and

total number of outcomes = total # of caps = 7 + 4 + 9 = 20

Finding the probability

<em>For </em><em>first </em><em>draw</em>

First let's find the probability that caleb will select a blue cap the first time.

We know that probability = # of favorable outcomes / total # of outcomes

We also know that # of favorable outcomes = 9 and total # of outcomes = 20

Plugging this in, we get that the probability of Caleb randomly selecting a blue cap on the first draw is 9/20

<em>For </em><em>second </em><em>draw</em>

Because it says that caleb will not replace the cap when drawn it's important to subtract 1 from both the # of caps and # of blue caps

This results us in having # of favorable outcomes as 8 and total # of outcomes as 19

Plugging this in we get that the probability of Caleb drawing a blue cap the second time is 8/19

Finally to find the total probability of him selecting two blue caps in a row without replacing the first cap, we multiply the individual probabilities

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