Area would be 66
You would simply multiple the width be the height to get your area!
The <em>first</em> series uses a <em>linear</em> function with - 1 as <em>first</em> element and 1 as <em>common</em> difference, then the rule corresponding to the series is y = |- 1 + x|.
The <em>second</em> series uses a <em>linear</em> function with - 3 as <em>second</em> element as 2 as <em>common</em> difference, then the rule corresponding to the series is y = |- 3 + 2 · x|.
<h3>What is the pattern and the function behind a given series?</h3>
In this problem we have two cases of <em>arithmetic</em> series, which are sets of elements generated by a condition in the form of <em>linear</em> function and inside <em>absolute</em> power. <em>Linear</em> <em>functions</em> used in these series are of the form:
y = a + r · x (1)
Where:
- a - Value of the first element of the series.
- r - Common difference between two consecutive numbers of the series.
- x - Index of the element of the series.
The <em>first</em> series uses a <em>linear</em> function with - 1 as <em>first</em> element and 1 as <em>common</em> difference, then the rule corresponding to the series is y = |- 1 + x|.
The <em>second</em> series uses a <em>linear</em> function with - 3 as <em>second</em> element as 2 as <em>common</em> difference, then the rule corresponding to the series is y = |- 3 + 2 · x|.
To learn more on series: brainly.com/question/15415793
#SPJ1
Answer: 5.196152423
Step-by-step explanation: Logically considering it's a Rhombus all the sides are equal to each other. So you just need to find the area. In this case you find the area by multiplying the sin of the given angle by the square root of the given side. So, 6²×sin (60)=6²×√3/2=31.17691454. After finding the area you then have to divide the area by it's base to find the height. So, 31.17691454 ÷ 6 = 5.196152423.
I didn't round any of the numbers. Hopefully this is correct.
Sorry about the messy diagrams (never been good at creating them) and how long it took.
Isn’t it h?
extra words so i can actually post this reply
