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trapecia [35]
2 years ago
14

The equation of the line that is parallel to 4x+2 and passing through (5,15)

Mathematics
1 answer:
Mila [183]2 years ago
8 0

Answer:

y=4x-5.

Step-by-step explanation:

slop-interception form of the required line is y=kx+b, where k - slop, b - intercept;

1) to find value of k:

if the required line is parallel to the given line, then slop of the given line = slop of the required line, it means k=4 and the required line is y=4x+b;

2) to find the value of 'b':

if to substitute the given coordinates into the equation of the given line, then:

15=4*5+b, b= -5.

3) finally, y=4x-5

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Match each equation with its solution set. Tiles a2 − 9a + 14 = 0 a2 + 9a + 14 = 0 a2 + 3a − 10 = 0 a2 + 5a − 14 = 0 a2 − 5a − 1
sattari [20]
We have that

N 1)
a²<span> − 9a + 14 = 0 
</span>

Group terms that contain the same variable, and move the constant to the opposite side of the equation

(a² − 9a)=-14

Complete the square  Remember to balance the equation by adding the same constants to each side 

(a² − 9a+20.25)=-14+20.25

Rewrite as perfect squares

(a-4.5)²=6.25--------> (a-4.5)=(+/-)√6.25

a1=4.5+√6.25-----> a1=7

a2=4.5-√6.25-----> a2=2

the solution problem N 1 is the pair {7, 2}


N 2) 

a²<span> + 9a + 14 = 0
</span>

Group terms that contain the same variable, and move the constant to the opposite side of the equation

(a² + 9a)=-14

Complete the square  Remember to balance the equation by adding the same constants to each side 

(a² +9a+20.25)=-14+20.25

Rewrite as perfect squares

(a+4.5)²=6.25--------> (a+4.5)=(+/-)√6.25

a1=-4.5+√6.25-----> a1=-2

a2=-4.5-√6.25-----> a2=-7

the solution problem N 2 is the pair {-2,-7}

N 3) 

a² + 3a − 10 = 0

Group terms that contain the same variable, and move the constant to the opposite side of the equation

(a² + 3a)=10

Complete the square  Remember to balance the equation by adding the same constants to each side 

(a² + 3a+2.25)=10+2.25

Rewrite as perfect squares

(a+1.5)²=12.25------> (a+1.5)=(+/-)√12.25

a1=-1.5+√12.25-----> a1=2

a2=-1.5-√12.25-----> a2=-5

the solution problem N 3 is the pair {2, -5}


N 4)

a²<span> + 5a − 14 = 0
</span>

Group terms that contain the same variable, and move the constant to the opposite side of the equation

(a² + 5a) =14

Complete the square  Remember to balance the equation by adding the same constants to each side 

(a² + 5a+6.25) =14+6.25

Rewrite as perfect squares

(a+2.5)² =20.25-------> (a+2.5)=(+/-)√20.25

a1=-2.5+√20.25-----> a1=2

a2=-2.5-√20.25-----> a2=-7

the solution problem N 4 is the pair {2, -7}


N 5) 

a² − 5a − 14 = 0

Group terms that contain the same variable, and move the constant to the opposite side of the equation

(a² − 5a)=14

Complete the square  Remember to balance the equation by adding the same constants to each side 

(a² − 5a+6.25)=14+6.25

Rewrite as perfect squares

(a-2.5)²=2025--------> (a-2.5)=(+/-)√20.25

a1=2.5+√20.25-----> a1=7

a2=2.5-√20.25-----> a2=-2

the solution problem N 5 is the pair {7, -2}

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Step-by-step explanation:

HERE,

redius of a circle (r)=14 meters.

we know that,

\boxed{\red{\sf{circle~ circumference=2\times \pi \times r   }}} 

<u>According</u><u> </u><u>to</u><u> </u><u>the question</u><u>, </u>

circle circumference=

  • \tt{2\times \pi \times 14   }

      

  • \tt{2 \times \dfrac{22}{7} \times 14   }  

    

  • \tt{2 \times \dfrac{22}{\cancel{7}} \times \cancel{14}}    

  

  • \tt{2\times 22 \times 2   }   

   

  • \tt{ 88~meters   }      

so, the circumference of that circle is <em><u>8</u></em><em><u>8</u></em><em><u> </u></em><em><u>meters</u></em><em><u>.</u></em>

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(01.01 MC)Why is 1 + (−5) equal to −4? I NEED HELP ASAPPPP
miv72 [106K]

Answer:

Hey there!

1+(-5)=1-5

1-5 = -4

Let me know if this helps :)

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What is the measure of angle b when the legs are 16, 16, 11?
KATRIN_1 [288]
What is opposite, adjacent to this angle?
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A contractor is building a fenced-in area at a daycare. The area will be rectangular with the length of its base equal to half t
AlladinOne [14]

Answer:

The length of fencing will be 300\ ft

Step-by-step explanation:

Step 1

Find the dimensions of the rectangle

we know that

The area of a rectangle is equal to

A=bh

In this problem we have

A=5,000\ ft^{2}

so

5,000=bh -----> equation A

b=\frac{h}{2} -----> equation B

Substitute equation B in equation A

5,000=(\frac{h}{2})h

10,000=h^{2}

square root both sides

h=100\ ft

Find the value of b

b=\frac{h}{2} -----> b=\frac{100}{2}=50\ ft

step 2

Find the length of fencing

The perimeter of a rectangle is equal to

P=2(b+h)

we have

h=100\ ft

b=50\ ft

substitute

P=2(50+100)=300\ ft

6 0
3 years ago
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