We know that
the equation of a circle is
(x-h)²+(y-k)²=r²
where
(h,k)-----> is the center
r--------> is the radius
is the center is the point (0,0) and radius r=20
then
(h,k) is (0,0)
(x-0)²+(y-0)²=20²---------> (x)²+(y)²=400
the answer is
the option D.) x2 + y2 = 400
Answer:
The solutions are x = 1.24 and x = -3.24
Step-by-step explanation:
Hi there!
First, let´s write the equation:
log[(x² + 2x -3)⁴] = 0
Apply the logarithm property: log(xᵃ) = a log(x)
4 log[(x² + 2x -3)⁴] = 0
Divide by 4 both sides
log(x² + 2x -3) = 0
if log(x² + 2x -3) = 0, then x² + 2x -3 = 1 because only log 1 = 0
x² + 2x -3 = 1
Subtract 1 at both sides of the equation
x² + 2x -4 = 0
Using the quadratic formula let´s solve this quadratic equation:
a = 1
b = 2
c = -4
x = [-b± √(b² - 4ac)]/2a
x = [-2 + √(4 - 4(-4)·1)]/2 = 1.24
and
x = [-2 - √(4 - 4(-4)·1)]/2 = -3.24
The solutions are x = 1.24 and x = -3.24
Have a nice day!
The answer is x=-9
Hope this helped:)
Answer:
I can't see the whole thing.
So sorry I can't answer it if I can't see the WHOLE thing.
Answer:
g(x+3) = -5x-15
Step-by-step explanation:
g(z) = -5z
g(x) = -5x
g(x+3) = -5(x+3)
= -5x -15
<em>Feel free to mark this as brainliest! :D</em>
