Select all the correct answers. Which triples are Pythagorean triples?

Mathematics

1 answer:

Fittoniya [83]3 years ago

3 0

The answer is in the picture below

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The area of a circle is 78.5 cm2. What is the diameter of the circle?

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Aida bought a costume box containing 50 costumes for $300. She sold all of the costumes and made a $250 profit. She sold all of

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Answer:$11

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Add 300 to both sides

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2 years ago

What are the indicated measures

marissa [1.9K]

1. Solve for N
Add all terms together and set equal to 360
(4n)+(9n+2)+(8n-12)+(5n+6)=360
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alina1380 [7]

Answer:

Theres quadrants so -3,9 would be lower about III

6,-6 would be IV

0,-1 1/2 That would be near the 0 obviously so II

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2 years ago

Precalc.

viktelen [127]

Domain: x>0.

$(\log_2x)^2+7\log_2x+12=0$

Substitute $t=\log_2x\in\mathbb{R}$ . We have:

$t^2+7t+12=0\\\\a=1\qquad b=7\qquad c=12\\\\\\\Delta=b^2-4ac=7^2-4\cdot1\cdot12=49-48=1\\\\\sqrt{\Delta}=\sqrt{1}=1\\\\\\
t_1=\dfrac{-b-\sqrt{\Delta}}{2a}=\dfrac{-7-1}{2}=\dfrac{-8}{2}=-4\\\\\\
t_2=\dfrac{-b+\sqrt{\Delta}}{2a}=\dfrac{-7+1}{2}=\dfrac{-6}{2}=-3$

For t₁ there will be:

$\log_2x=t_1\\\\\log_2x=-4\\\\2^{-4}=x\\\\x=\dfrac{1}{2^4}\\\\\\x=\dfrac{1}{16}=0,0625\\\\\\\boxed{x\approx0,063}$

and for t₂:

$\log_2x=t_2\\\\\log_2x=-3\\\\2^{-3}=x\\\\x=\dfrac{1}{2^3}\\\\\\x=\dfrac{1}{8}\\\\\\\boxed{x=0,125}$

Answer d)

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3 years ago