Select all the correct answers.<br> Which triples are Pythagorean triples?

andreev551 [17]

Since the 9 is greater than or equal to 5, we'll round our number up by adding 1 to the 3 in the hundreds place, making it a 4. And also by changing all digits to the right of this new 4 into zeros.

And our rounded number would be 400

3 0

4 years ago

The six Grade is holding a fundraiser were students will make and sell peace necklaces for $1.50 each each student is responsibl

kap26 [50]

Answer:

$ 584.89

Step-by-step explanation:

so each student is responsible for selling 12 necklaces...and there are 130 students....so thats (130 * 12) = 1560 necklaces

each necklace is 1.50....so thats (1560 * 1.50) = 2340

profit = revenue earned - expenses

profit = 2340 - 0.45 = 2339.55

1/4 of the profit goes to Puerto Rico

1/4 * 2339.55 = 2339.55/4 = 584.887 rounds to $ 584.89 <==

6 0

3 years ago

A zoologist is studying four very closely related feline species. She wishes to compare their gestation periods. An observationa

diamong [38]

Answer:

$p_v= 0.01$

Since the significance level is 0.05 we see that $pv$ so we have enough evidence to reject the null hypothesis. And the best conclusion for this case would be:

b. at least some, but not all, of the gestation periods across all four species are the same

Because is only to identify if AT LEAST one mean is different, NOT to conclude that the all the means are different.

Step-by-step explanation:

Previous concepts

Analysis of variance (ANOVA) "is used to analyze the differences among group means in a sample".

The sum of squares "is the sum of the square of variation, where variation is defined as the spread between each individual value and the grand mean"

Solution to the problem

The hypothesis for this case are:

Null hypothesis: $\mu_{A}=\mu_{B}=\mu_{C}= \mu_D$

Alternative hypothesis: Not all the means are equal $\mu_{i}\neq \mu_{j}, i,j=A,B,C,D$

In order to find the mean square between treatments (MSTR), we need to find first the sum of squares and the degrees of freedom.

If we assume that we have $p=4$ groups and on each group from $j=1,\dots,p$ we have $n_j$ individuals on each group we can define the following formulas of variation:

$SS_{total}=\sum_{j=1}^p \sum_{i=1}^{n_j} (x_{ij}-\bar x)^2$

$SS_{between}=SS_{model}=\sum_{j=1}^p n_j (\bar x_{j}-\bar x)^2$

$SS_{within}=SS_{error}=\sum_{j=1}^p \sum_{i=1}^{n_j} (x_{ij}-\bar x_j)^2$

And we have this property

$SST=SS_{between}+SS_{within}$

And in order to test this hypothesis we need to ue an F statistic and for this case the p value calculated is

$p_v= 0.01$

Since the significance level is 0.05 we see that $pv$ so we have enough evidence to reject the null hypothesis. And the best conclusion for this case would be:

b. at least some, but not all, of the gestation periods across all four species are the same

Because is only to identify if AT LEAST one mean is different NOT to conclude that the all the means are different.

8 0

4 years ago

Whats the answer for this one plz

Pavlova-9 [17]

Answer:

Step-by-step explanation:

X = 90°

4 0

3 years ago

Read 2 more answers

Each side of the regular hexagon below measures 8 cm. What is the area of the hexagon?

sineoko [7]

A regular hexagon can be split into 6 congruent equilateral triangles.
the area of an equilateral triangle is √3*s²/4, where s is the side length
Area of the hexagon
= 6*√3*8²/4
= 96√3 square centimeters

6 0

3 years ago

Read 2 more answers

Select all the correct answers. Which triples are Pythagorean triples?