3 years ago

Select all the correct answers. Which triples are Pythagorean triples?

Mathematics

1 answer:

Fittoniya [83]3 years ago

3 0

The answer is in the picture below

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IgorLugansk [536]

Answer:

LCM of 3 and 2 is 6

so, firstly we had to make the denominator same:-

$\frac{2(2a + 1) + 3(3a - 1)} {6}$

$\frac{4a + 2 + 9a - 3}{6}$

$\frac{13a - 1}{6}$

Step-by-step explanation:

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3 years ago

A coin and a dice are tossed at the same time.

Aleksandr-060686 [28]

Answer:

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Step-by-step explanation:

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Read 2 more answers

What are the real and complex solutions of the polynomial equation X^3-216=0

vazorg [7]

Answer:

$6,\ -3+3\sqrt{3}i,\ -3-3\sqrt{3}i$

Step-by-step explanation:

Factor the equation $x^3-216=0$ using formula for difference of the cubes:

$x^3-216=(x-6)(x^2+6x+36),$

then

$x-6=0\ or\ x^2+6x+36=0.$

1. The equation $x-6=0$ has real solution $x=6.$

2. The equation $x^2+6x+36=0$ has negative discriminant $D=6^2-4\cdot 36=36-144=-108,$ then it has two complex solutions

$x_{1,2}=\dfrac{-6\pm 6\sqrt{3}i}{2}=-3\pm3\sqrt{3}i.$

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3 years ago