Write the formula for a function d(x) that describes the distance between the point P and a point (x,y) on the line. You final a
nswer should only involve the variable x. Then d(x) =
1 answer:
Answer:
d(x) = √[(x - 2)² + (3x - 1)²]
Step-by-step explanation:
The distance between two points with coordinates (x₁, y₁) and (x₂, y₂) is given as
d = √[(x₂ - x₁)² + (y₂ - y₁)²]
So, the distance between point (2,0) and a point (x,y)
d = √[(x - 2)² + (y - 0)²]
d = √[(x - 2)² + (y)²]
But the point (x,y) is on the line y = 3x - 1
We can substitute for y in the distance between points equation.
d(x) = √[(x - 2)² + (3x - 1)²]
QED!
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Answer:
Step-by-step explanation:
The given polynomial has zeros at:
x=−3, x=−1, and x=1.
This means that:
x+3, x+1, and x-1 are all factors of this polynomial.
The factored form of this polynomial is :
We expand the last two factors using difference of two squares.
This is the standard form because it is now in decreasing powers of x.