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Molodets [167]
2 years ago
5

You dilate a figure with respect to the origin using a scale factor of 4, and then reflect the image in the y-axis. Complete the

coordinate notation to show how the coordinates of the original figure are related to the coordinates of the final image after the transformations.
Mathematics
1 answer:
7nadin3 [17]2 years ago
6 0

Answer:

Step-by-step explanation:

Answer:

I think it is too large

Explanation:

Too much people = too much loving

Ayer me dijeron tus amigas

Que andabas buscándome como loca en la calle

Y yo bebiendo como loco cerveza

Con unos parceros dañándome la cabeza

Borracho con el corazón malo

Caminando solo

Me la encontré a ella

Mujer tan bella

Yo con una botella

Me dejé enredar fácil

Caí en las garras de ella

Mujer tan bella

Yo con una botella

Me dejé enredar fácil

Caí en las garras de ella

Me dijeron que andabas un poco triste

Que te pusiste a beber y con un man por ahí te fuiste

Ay baby, me dañaste el corazón

Ya no creo en el amor

Ahora por ti soy peor

Ay baby, me dañaste el corazón

Ya no creo en el amor

Ahora por ti soy peor

Yo me fui a matar mi despecho

En la lluvia, en la calle sin techo

Pensando con quién te fuiste mujer

Qué te hice yo que no vas a volver

Mujer tan bella

Yo con una botella

Me dejé enredar fácil

Caí en las garras de ella

Mujer tan bella

Yo con una botella

Me dejé enredar fácil

Caí en las garras de ella

Ayer me dijeron tus amigas

Que andabas buscándome como loca en la calle

Y yo bebiendo como loco cerveza

Con unos parceros dañándome la cabeza

Borracho con el corazón malo

Caminando solo

Me la encontré a ella

Mujer tan bella

Yo con una botella

Me dejé enredar fácil

Caí en las garras de ella

Mujer tan bella

Yo con una botella

Me dejé enredar fácil

Caí en las garras de ella

Wolfine

La versatilidad de la calle

DJ GANSTA

En el ritmo que te provoca

Lucas y Mauri

Lo mío records

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Elodia [21]

Answer:

\sf x=1+i\sqrt{\dfrac{2}{3}}   \ \quad and  \quad \:x=1-i\sqrt{\dfrac{2}{3}}

Explanation:

<u>Given Expression</u>:

  • 3x² - 6x + 5 = 0

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\sf x = \dfrac{ -b \pm \sqrt{b^2 - 4ac}}{2a}  \  \ when   \ \  ax^2 + bx + c = 0

<u>insert coefficients</u>

\Longrightarrow \sf x = \dfrac{-\left(-6\right)\pm \sqrt{\left(-6\right)^2-4\cdot \:3\cdot \:5}}{2\cdot \:3}

\Longrightarrow \sf x = \dfrac{\left6\right\pm \sqrt{-24} }{6}

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2 years ago
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