-24a²- 6a +9 = - 3(8a² +6a - 9)
8a² +6a - 9 =0
x=(-b +/-√(b² - 4ac))/2a
x = (-6 +/-√(36+4*8*9) /(2*8) = (-6 +/-√(324) /16 = (-6 +/-18)/16
x1 = (-6 +18)/16 = 0.75
x2 = (-6 -18)/16 = - 1.5
-24a²- 6a +9 = - 3(8a² +6a - 9) = -3(a - 0.75)(a + 1.5)
-2m - 5m = -7m
-7m - 8 = 3 -7 + m
3 - 7 = -4
-7m - 8 = m - 4
-7m - 8 + 8 = m - 4 + 8
-7m = m + 4
-7m - m = m + 4 - m
-8m = 4
-8m/-8 = 4/ -8
FINAL = m= -1/2 = -0.5
Answer:
x< -11/2
Step-by-step explanation:
Let's solve your inequality step-by-step.
2(4x+1)<3(2x−3)
Step 1: Simplify both sides of the inequality.
8x+2<6x−9
Step 2: Subtract 6x from both sides.
8x+2−6x<6x−9−6x
2x+2<−9
Step 3: Subtract 2 from both sides.
2x+2−2<−9−2
2x<−11
Step 4: Divide both sides by 2.
2x/2<−11/2
x< −11/2
You would need to shade 1.5 boxes or 6 pieces to have shaded 25% of the shape.
In total, there are 6 boxes. There are 4 pieces per box. In total, there are 24 pieces.
6/4 = 1.5
24/4 = 6
You would need to shade 1.5 boxes, which is equal to 6 pieces or triangles.
hello :<span>
<span>an equation of the circle Center at the
O(a,b) and ridus : r is :
(x-a)² +(y-b)² = r²
in this exercice : a =0 and b = 0 (Center at the origin)
r = AO
r² = (AO)²
r² = (4-0)² +(5-0)² = 16+25=41
an equation of the circle that satisfies the stated conditions.
Center at the origin, passing through B(4, 5) is : x² +y² = 41</span></span>
x² +y² - 41=0
