Answer: Choice D
b greater-than 3 and StartFraction 2 over 15 EndFraction
In other words,
b > 3 & 2/15
or

========================================================
Explanation:
Let's convert the mixed number 2 & 3/5 into an improper fraction.
We'll use the rule
a & b/c = (a*c + b)/c
In this case, a = 2, b = 3, c = 5
So,
a & b/c = (a*c + b)/c
2 & 3/5 = (2*5 + 3)/5
2 & 3/5 = (10 + 3)/5
2 & 3/5 = 13/5
The inequality
is the same as 
---------------------
Let's multiply both sides by 15 to clear out the fractions

---------------------
Now isolate the variable b

Side note: Another way to go from 47/15 to 3 & 2/15 is to notice how
47/15 = 3 remainder 2
The 3 is the whole part while 2 helps form the fractional part. The denominator stays at 15 the whole time.
Answer:
linear
Step-by-step explanation:
Answer: 3.36
Step-by-step explanation:
hello. My name is Mary. I am in 7th grade.
So On the left side you see that it is division so you do the inverse operation which is multiplication. You cross out x/8 and go to the right side . .42 times 8 s 3.36. X=3.36.
9514 1404 393
Answer:
a square 175 m on a side
Step-by-step explanation:
Let x and y represent the sides of the rectangle. Then the perimeter is ...
P = 2(x + y) = 700
x + y = 350 . . . . . . . divide by 2
y = 350 -x . . . . . . . . subtract x
The area of the fenced field is ...
A = xy
A = x(350 -x)
This is a quadratic function that has zeros at x = 0 and x = 350. The axis of symmetry is x = (0 +350)/2 = 175. The vertex (maximum area) is on the axis of symmetry, so corresponds to x = 175. The y-value there is ...
y = 350 -x = 350 -175 = 175
That is, the maximum area will be obtained when the fenced area is a square. Each side of the square is 175 m, which is 1/4 of the total length of the fence.
The dimensions of the space are 175 m by 175 m.