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hammer [34]
3 years ago
14

A neutral solution has....

Biology
1 answer:
Nutka1998 [239]3 years ago
7 0
Yo sorry I was in the bed and west lol I
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Example of active transport would be
Mrac [35]

Answer:

c. sodium-potassium pump

Explanation:

a. osmosis - this is a type at of passive transport. It is diffusion specific to water molecules.

b. diffusion - this is also a type of passive transport. Molecules move from a high concentration to a low concentration down a concentration gradient. This is passive transport and does not require energy.

c. A sodium-potassium pump is a type of active transport, it uses energy to move ions across the membrane. They cannot pass through the membrane because they are charged.

d, facilitated diffusion is a type of passive transport through which substances are transported through proteins in the plasma membrane.

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3 years ago
Which diet instructions are appropriate when teaching a client in the early stages of cirrhosis about nutritional needs? select
Reika [66]
<span>Adequate intake of protein is important and small, frequent meals are best for proper caloric intake. The protein does not need to be restricted until the later stages of cirrhosis. Gastrointestinal issues can make it difficult for a person with cirrhosis to handle three standard meals a day, so having more meals but in smaller portions can make the GI tract more functional.</span>
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4 years ago
What are in protista which help them in locomotion ?​
Masteriza [31]

They work coordinately by beating movements and helps the protists to move. ... Therefore, the important locomotory organelles in protists are flagella, cilia and pseudopodia. Flagella is a single, slender long structure while cilia are numerous in number. Cilia helped in locomotion by the synchronized beating movements.

3 0
3 years ago
Which of the following is a producer?
Lerok [7]

Answer:

D

Explanation:

4 0
4 years ago
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A restriction enzyme has a 4 bp recognition sequence. Assuming equal frequency of all four bases in a 5,000 bp linear section of
I am Lyosha [343]

Answer: 20 fragments

Explanation:

This particular restriction enzyme has a 4 bp (base pair) recognition sequence therefore it will cleave once every 4ⁿ bases where n indicates the number pf bases in the recognition sequence.

  • The recognition sequence is 4 bp therefore this restriction enzyme cleaves once every 4⁴ = 256 bases. This is the length of the restriction fragment.
  • Calculate the number of fragments by dividing the total number of bases ( where you assume equal frequency of bases ie. A+T = C+G) by the length of the restriction base.
  • therefore 5000bp/256bp = <u>19,53</u> now this number ca n be rounded up to 20.
  • The expected number of fragments on the electrophoresis gel will be 20 fragments.

5 0
4 years ago
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