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Vika [28.1K]
4 years ago
8

A restriction enzyme has a 4 bp recognition sequence. Assuming equal frequency of all four bases in a 5,000 bp linear section of

DNA, how many fragments (rounded answer) would you expect to see on an electrophoresis gel?
Biology
1 answer:
I am Lyosha [343]4 years ago
5 0

Answer: 20 fragments

Explanation:

This particular restriction enzyme has a 4 bp (base pair) recognition sequence therefore it will cleave once every 4ⁿ bases where n indicates the number pf bases in the recognition sequence.

  • The recognition sequence is 4 bp therefore this restriction enzyme cleaves once every 4⁴ = 256 bases. This is the length of the restriction fragment.
  • Calculate the number of fragments by dividing the total number of bases ( where you assume equal frequency of bases ie. A+T = C+G) by the length of the restriction base.
  • therefore 5000bp/256bp = <u>19,53</u> now this number ca n be rounded up to 20.
  • The expected number of fragments on the electrophoresis gel will be 20 fragments.

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